[SI-LIST] Re: (no subject)

  • From: "Doug White" <dowhite@xxxxxxxxx>
  • To: <vincesanity05@xxxxxxxxx>, <si-list@xxxxxxxxxxxxx>
  • Date: Tue, 4 Nov 2003 14:14:03 -0500

I believe the answer to the first question would be that one needs to know
the relative phase of the current and voltage of the circuit in question.
In order to have power dissipation, the current must be in-phase with the
voltage.

Doug

-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx
[mailto:si-list-bounce@xxxxxxxxxxxxx]On Behalf Of vince vintero
Sent: Tuesday, November 04, 2003 5:42 AM
To: si-list@xxxxxxxxxxxxx
Subject: (no subject)


HI...my name's Vince and i'm an ET student. We were given a homework and I
was researching through "Ask Jeeves" and i saw a link where you answered
someone's question for their project.
My question is this: Why is it that using measurement of a circuit's voltage
with a voltmeter and its current with an ammeter does not provide the
necessary info to find the actual power dissipated by the circuit? And is
the tuned circuit of a receiver typically series or parallel LC circuit?
Hope you can provide me the info i need....i'd really appreciate it...thanks
so much

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