Hi, I am using a AMP DIN Connector which has a current carrying capacity of 1.5A at 20 degrees. Basically I am using it as a board to board connector. I am using the same connnector to deliver power also. What I wanted to ask was that if I route the same VCC signal to say 6 pins then the VCC signal should be able to carry 6x1.5A =9A . Say the resistance of the pin is 10mohm then the max volatge drop would be 1.5 x .01= 15mV. Apart from the extra power consumption is there any other problem in doing this kind of design. I know there are higher current carrying connector but I have space issues on the board hence it would be nice if I could do it this way. Thanks in advance. Regards,Christy --------------------------------- Do you Yahoo!? Yahoo! Mail Plus - Powerful. Affordable. Sign up now ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu