[ascoders] Re: Wippe Physik
- From: André Michelle <am@xxxxxxxxxxxxxxxxxx>
- To: <ascoders@xxxxxxxxxxxxx>
- Date: Fri, 30 Jan 2004 11:25:41 +0100
> Ich sage mal, das ist eine Zahl und kein Vektor, aber an der Stelle
> der Wippe, wo Du dann die Kraft wieder rauskommen läßt, verwandelt
> sich das dann ja wieder umgekehrt in einen Vektor. Aber ich habe
> jetzt gerade in keinem Buch nachgesehen.
Aus: http://myphysicslab.com/collision.html
Actually torque is a vector, but since we are working in 2 dimensions we
know that torque is always perpendicular to the plane and so we aren't using
vector notation for it. The true vector cross product results in a vector.
So the above cross product corresponds to the following 3 dimensional
calculation:
(Rx, Ry, 0) × (Tx, Ty, 0) = (0, 0, Rx Ty - Ry Tx)
Aha! Klar, in 3d wäre es ein 2d Vector.
Aber ist es korrekt einfach das Drehmoment auf die Winkelgeschwindigkeit
hinzuaddieren ? Scheinbar ja...
--
aM
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- [ascoders] Re: Wippe Physik
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