The figures are as follows: A satellite of mass 300 kg will weigh 2,942 N at mean sea level 66 N at the parking orbit altitude under Newton's formula 0.0577 N at the parking orbit altitude under my formula. To put this into perspective, the force pulling the satellite back down under my formula is equivalent to the force you have to exert to lift a quarter of an ounce weight off your kitchen scales. Not much, but certainly not zero. Neville. philip madsen <pma15027@xxxxxxxxxxxxxx> wrote: Bernie, I'm not expert here, but there is no real "zero gravity", as regards the force "field" Notice I enclosed "field" because it is a mathmatical abstract to represent visually what is only hypothetical. The field of force is technically everywhere, even in a neutral zone. What we are getting confused with is weight. or weightlessness. We experience this phenomena during free fall. You might recall seeing these free fall experiments in high flying aircraft. A satellite in orbit is in a continuous "free fall " mode, as it technically falls "towards" but around the earth. It looks as though no one offered the means to calculate the weight of an object within the gravitational field, so I'll do a quick search and get back to us. we should be able to calculate exactly the weight (force) due to gravity at 22000miles up. but I just hate the metric system because it converted simple pounds into a Jewish name... I do not think it is a conspiracy here as regards the orbiting objects and the formulars used, The devil may know, but these guys are just believing blindly what to them seems a rational concept. The world does not produce many Faradays or Teslas like us you know... Philip. --------------------------------- Copy addresses and emails from any email account to Yahoo! Mail - quick, easy and free. Do it now...