[SI-LIST] Re: Right Angle Bends

  • From: Scott McMorrow <scott@xxxxxxxxxxxxx>
  • To: Jack Olson <pcbjack@xxxxxxxxx>
  • Date: Wed, 20 Jul 2011 08:58:06 -0400

Jack
I've decided to put some numbers to the Right Angle Bend discussion, 
since it's nice to know when we need to be concerned about a particular 
physical phenomena.

Your point regarding round apertures on traces is important, although 
slightly misleading.  A round aperture is applied to the end of a trace 
with the center of the radius at the center of the trace width, such 
that the outside apex is rounded, while the inside apex is square.  
Thus, a trace corner with circular end apertures still has excess 
capacitance when compared to the optimal RF miter[1].  If we use 
Bogatin's approximation of a 50% miter (corner sliced diagonally in the 
center at 45 degrees, which is not quite correct, but is close) to 
compute the excess capacitance, then using a circular end aperture on 
traces at corners reduces capacitance by (1-pi/4), or about 21%, which 
helps, but still leaves us with excess capacitance.

Here are some calculations based on Bogatin, "Signal Integrity 
Simplified", page 317, which I've verified:

    Square corner capacitance(pf) = 40/Z0 x sqrt(Er) x w
    where w = width in inches
    Er = dielectric contstant
    Z0 = characteristic impedance of trace

50 ohm impedance, Er = 4

10 Gbps (5 GHz Nyquist) with square apertures.
Case 1) A 100 mil wide trace - 160 fF  = 199 ohm shunt Z at 10 GHz, 
produces a 40 ohm tdr blip for 17 ps (17% UI).
Case 2) A 10 mil wide trace - 16 fF = 1990 ohm shunt Z at 10 GHz, 
produces a 48.8 ohm tdr blip for 1.7 ps (1.7% UI).
Case 3) A 5 mil wide trace - 8 fF = 3980 ohm shunt Z at 10 GHz, produces 
a 49.4 ohm tdr blip for 850 fs (0.85% UI).
Case 4) A 1 mil wide trace - 1.6 fF = 19900 ohm shunt Z at 10 GHz, 
produces a 49.75 ohm tdr blip for 170 fs (0.2% UI).

20 Gbps (10 GHz Nyquist) with square apertures.
Case 1) A 100 mil wide trace - 160 fF  = 99 ohm shunt Z at 10 GHz, 
produces a 33 ohm tdr blip for 17 ps (34% UI).
Case 2) A 10 mil wide trace - 16 fF = 995 ohm shunt Z at 10 GHz, 
produces a 47.6 ohm tdr blip for 1.7 ps. (3.6% UI).
Case 3) A 5 mil wide trace - 8 fF = 1990 ohm shunt Z at 10 GHz, produces 
a 48.8 ohm tdr blip for 850 fs (1.7% UI).
Case 4) A 1 mil wide trace - 1.6 fF = 9947 ohm shunt Z at 10 GHz, 
produces a 49.75 ohm tdr blip for 170 fs (0.3% UI).

20 Gbps (10 GHz Nyquist) With circular end apertures on traces (reduce 
excess shunt capacitance by 21%)
Case 1) A 100 mil wide trace - 126 fF  = 126 ohm shunt Z at 10 GHz, 
produces a 36 ohm tdr blip for 17 ps (34% UI).
Case 2) A 10 mil wide trace - 12.6 fF = 1265 ohm shunt Z at 10 GHz, 
produces a 48 ohm tdr blip for 1.7 ps (3.4% UI).
Case 3) A 5 mil wide trace - 6.3 fF = 2530 ohm shunt Z at 10 GHz, 
produces a 49 ohm tdr blip for 850 fs (1.7% UI).
Case 4) A 1 mil wide trace - 1.26 fF = 12650 ohm shunt Z at 10 GHz, 
produces a 49.8 ohm tdr blip for 170 fs (0.3% UI).


So, for real traces, on real boards, with real CAD end apertures, a 
single corner on traces that are 1 mil to 10 mil wide, at frequencies of 
10 GHz or below, neffectively cannot be measured without specialized 
de-embedding methods. The discontinuity is too small and too short.  For 
microwave width traces, those corners are large discontinuities with 
real consequences.

If we happen to be running at 56 Gbps (28 GHz Nyquist)
Case 2) A 10 mil wide trace - 12.6 fF = 452 ohm shunt Z at 10 GHz, 
produces a 45 ohm tdr blip for 1.7 ps (9.5% UI).
Case 3) A 5 mil wide trace - 6.3 fF = 604 ohm shunt Z at 10 GHz, 
produces a 46 ohm tdr blip for 850 fs (4.8% UI).
Case 4) A 1 mil wide trace - 1.26 fF = 4518 ohm shunt Z at 10 GHz, 
produces a 49.5 ohm tdr blip for 170 fs (0.9% UI).

Conclusions:

    * There is nothing wrong with the information about square corners
      found in the RF and Microwave literature.  It applies to the wide,
      low loss traces used in RF design, and is quite correct, corners
      do matter.
    * For digital designs traces of 10 mil width or less are generally
      used, and as such corner design is essentially unimportant, due to
      the benefit of size scaling on reduction in the size and duration
      of the discontinuity.
    * As a figure of merit, I'd suggest we use 5% of UI, and +/- 5% Z0
      as the point that we start considering that a particular type of
      discontinuity matters for SerDes channels.  This is conservative,
      but I like being conservative, and working with positive margin,
      rather than fighting against negative margin.
    * Up to 20-ish Gbps, 90 degree CAD layout corners on traces up to 10
      mil in width have no significant impact on the signal.
    * At 56 Gbps, 90 degree CAD layout corners become significant
      starting at 5 mil width.
    * At 28 Gbps and 56 Gbps designers may be fighting high copper and
      dielectric losses, forcing the usage of low loss dielectrics (tanD
      < 0.005), smooth copper foils (surface roughness < 0.4 micron
      RMS), and wider traces.  In these cases, corner mitering, or
      routing of traces using circular arcs, might be considered, when
      traces are wider than 10 mil @ 28 Gbps and 5 mil @ 56 Gbps.


Another way to look at corners is from the view of a transmission line 
with distributed loading.  On page 317 of Eric Bogatin's book, he shows 
his geometric derivation for the computation of corner capacitance.  We 
can reduce his geometry into 3 square cells at a corner, which can be 
further divided into 6 equal sized triangular sections.  One triangular 
section represents the excess corner capacitance.  If we call this the 
"unit corner cell" then it's clear that corner capacitance represents an 
increase of the capacitance of the entire cell by 6/5, or 1.2.  Knowing 
this we can compute the distributed Impedance of the line as 
Z(distributed) = Z0 x sqrt(5/6) = 0.91 Z0.  For 50 ohm impedance, that 
amounts to a distributed transmission line impedance of 45.6 ohms.  So, 
if we were to cascade corners in a diagonal stairstep fashion, the 
distributed impedance of the line would asymptotically approach around 
45 ohms, since the capacitance becomes averaged across a longer 
distance. This is independent of the line width.  In addition, the 
distributed delay of the transmission line is increased by sqrt(6/5) or 
by 1.095, across the unit cell section, or about 16 ps per inch of 
additional delay for Er=4.

So where could we have a problem?  Using the distributed version of the 
analysis, we can see that stair step type structures might accentuate 
corner capacitance issues.  One place where this can happen is in the 
routing escape pin fields of BGA and connectors.  Another is the 
increase in actual delay that can be seen in trace delay matching 
serpentine sections.  Even if coupling between serpentine sections is 
minimized, a unit rectangular serpentine section has 4 corners.  For 5 
mil trace width, each corner has an excess capacitance of 6.3 fF, an 
incremental delay adder of about 300 fs.  For the 4 corners of a 
serpentine section, there is 1.2 ps of additional delay, not accounted 
for by net length calculations.  Short squarish delay matching sections 
(so called delay bumps or blips along a line) with 4 corners per blip 
will experience a large percentage increase in delay over the net length 
calculation vs. longer rectangular delay matching sections, with fewer 
total number of corners.

Real world?  It depends on the world you're designing in.

best regards,

Scott


1. Experimental derivation of optimal miter can be found in:  R. J. P. 
Douville and D. S. James, Experimental study of symmetric microstrip 
bends and their compensation; IEEE Trans. Microwave Theory Tech., vol. 
MTT-26, pp. 175-182, Mar. 1978.


Scott McMorrow
Teraspeed Consulting Group LLC
121 North River Drive
Narragansett, RI 02882
(401) 284-1827 Business
(401) 284-1840 Fax

http://www.teraspeed.com

Teraspeed® is the registered service mark of
Teraspeed Consulting Group LLC


On 7/18/2011 10:14 AM, Jack Olson wrote:
> Speaking from the board designers point of view:
> I may never understand why people use square corners in their models when
> they want to experiment with this subject. Are we talking about 90 degree
> bends? or drawing traces with square corners? Maybe it is interesting from a
> mathematical point of view, but I've never met a board designer who used
> square apertures to draw traces. Every modern board design I've ever seen
> (by modern I mean designed in a CAD system , not the old manual tape
> layouts) uses round apertures, and when using a round aperture the width is
> always constant, no matter how you "bend" the trace.
> Furthermore, I haven't seen too many designs where the bends weren't 45
> degrees anyway, why would anyone route 90 degree bends? longer runs, in most
> cases.... but theoretically I suppose its interesting to discuss.
> Real world? not so much.
>
> onward thru the fog,
> Jack
>
>
> .
> Date: Fri, 15 Jul 2011 16:56:38 -0400
> From: Scott McMorrow<scott@xxxxxxxxxxxxx>
> Subject: [SI-LIST] Re: Right Angle Bends
>
> Lee
>
> It's not so much "misinformation" but "misapplication" of information.
> The "no right angle bend rule" makes perfect sense on RF microstrip
> boards where the traces are about 1 or 2 mm from the plane, and are
> extremely wide.  When you're dealing with 50 ohm traces that are 100
> mils wide, excess capacitance at the corner is a big deal, since the
> discontinuity acts for about 140 mils in distance (the diagonal across
> the corner).  If built on an FR4-type material with a Dk = 4, this
> corner discontinuity has about a 25 ps time duration, which can be
> significant.  Additionally, RF engineers are always trying to reduce
> narrow band return loss to extremely low levels, far beyond that which
> is necessary for broadband digital.
>
> However, when we scale the traces down to 5 mil width, the discontinuity
> is same relative size, but 1/20th the physical size, and acts for only
> about 7 mils, or about 1.25 ps.   IF a 1.25 ps discontinuity is a big
> deal to an engineer then this might matter, or if you have 20 corners,
> the cumulative effect of this discontinuity will span a duration of 25
> ps, or 1/4 of a 10 Gbps bit time.  But 1.25 ps of excess capacitance
> does not matter until we designing for 50 Gbps, and only a fool would
> route a trace with 20 corners in it, so effectively corners are not an
> issue.
>
> Lee, you are correct.
>
> Scott
>
> Scott McMorrow
> Teraspeed Consulting Group LLC
> 121 North River Drive
> Narragansett, RI 02882
> (401) 284-1827 Business
> (401) 284-1840 Fax
>
> http://www.teraspeed.com
>
> Teraspeed® is the registered service mark of
> Teraspeed Consulting Group LLC
>
>
> On 7/15/2011 3:15 PM, Lee Ritchey wrote:
>> That is another urban legend.  Never been true.  I've seen fabricators say
>> this and then etch outer layers with all sorts of surface mount pads that
>> have traces entering them that result in right angle corners and never
>> complain!
>>
>> We'll probably all go to our graves before we flush out all this
>> misinformation!
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