Hi Andy/Steve, It makes sense that inductor is not parallel to basic capacitor instead stray capacitance is parallel to series inductance. Thanks a lot for clearing the doubts and explaining things in detail !! Rgds, Rohit -----Original Message----- From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On Behalf Of Andrew Ingraham Sent: Friday, May 13, 2011 11:33 PM To: si-list@xxxxxxxxxxxxx Subject: [SI-LIST] Re: Parallel Inductor in Capacitor !!! > What I am trying to ask is how come parallel inductor is possible > in parallel plate capacitor geometry ? All the conductor like pins & > plates come in series with capacitor so we should see only series > not parallel inductor, right ? Read and understand Steve's reply. But you can also step back and consider SOME OF the lumped elements in the model as representing real physical parts of the capacitor. Your basic capacitor, at the heart of the physical capacitor, is C1. Look closely at it. It has NO inductors in parallel with it. The only thing in parallel with it is R100, perhaps representing the leakage resistance of the dielectric, or maybe just to keep SPICE happy. The plates that make up the capacitor, and its leads (if any), have some inductance and DC and AC resistance. Those are represented by all of the other elements in series with C1. That includes L2, L5, L6, L7, and L8, all of which are in series with the basic capacitor, C1 ... not in parallel with it. Why are there five inductances in series with C1? We can't really say for sure (because the model was probably derived on the basis of curve-fitting the impedance to measurements). But consider the fact that even these lead inductances have stray capacitances across them and perhaps distributed along them. The impedance of an ideal inductance increases linearly, without bounds, as frequency goes up. The lead inductance probably does not, due in part to those stray capacitances. So the model (the RLC series circuit) needs to be modified to make the inductive reactance behave correctly, by splitting it into five portions and putting capacitances and resistors across some of them. L2 apparently represents that portion of the lead inductance that is not shunted by any stray capacitance. However, the further you look into the exact details of the model, the less likely each part represents an actual physical analog in the capacitor, the more likely they are there to make the total impedance curve fit what they measured. Consider it this way. It's not that the capacitor has an inductor in parallel with it. It doesn't. It's that the inductors which are in series with the capacitor (C1), need to have some additional capacitances added in parallel with them. I'm trying to answer the question you didn't ask, which is, why are there capacitors put in parallel with the lead inductance? Andy ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List technical documents are available at: http://www.si-list.net List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List technical documents are available at: http://www.si-list.net List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu