Steven, remember that FindGraphic returns an integer. So: if ( FindGraphic(0,"Next record",S_Top,S_Restricted)) then LeftMouseButton() endif On 7/17/12, Steven Hicks <Steven.HicksSM@xxxxxxxxxxxxx> wrote: > Hi friends, > > > I have an application which has a line of four buttons which don't appear > to > be standard graphical buttons, they are graphics which I have to manually > label. > > I have written a script using the FindGraphic(0,"Next in > list",S_Top,S_Restricted). key word and it seems to work and find the > graphic fine. > > I would like to expand this script so that I can confirm that I am on the > graphic and if so, I would then like to perform a left mouse botton to > click > it. > > Does anyone have any suggestions on how I may do this please? > > My script looks like the following at the moment: > > > > Script(NextRecord) > > FindGraphic(0,"Next record",S_Top,S_Restricted) > > EndScript() > > > > Any help would be much appreciated, > > > > Steve. > > > > P.s. I could even consider using the IfSameKey I think it is so that I > press the assigned shortcut key twice to execute the left mouse button. > > > > Take care all. > > > > > > > > __________� > > View the list's information and change your settings at > //www.freelists.org/list/jawsscripts > > -- Blame the computer--why not? It can't defend itself & occasionally might even be the culprit Jackie McBride Ask Me Computer Questions at: www.pcinquirer.com Jaws Scripting training materials: www.screenreaderscripting.com homePage: www.abletec.serverheaven.net __________� View the list's information and change your settings at //www.freelists.org/list/jawsscripts