If he takes a picture in the radial direction at various locations along the curved path, then the photographer has performed A ROTATION + A TRANSLATION If his orientation in space does not stay the same, then, per definition, he has performed a rotation. It is that simple. Regner - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Quoting Allen Daves <allendaves@xxxxxxxxxxxxxx>: > You realy did not read that at all did you....I said regardless of the path > (translational directional) if the observer takes the photo in a radial > postion ( this is the contion of the earth every 24 hours) he will most > certainly see a Rotaion...We are not going to be abel to get anywhere untill > you are able to grasp this....Please let me know what you do not > understand..... > > Regner Trampedach <art@xxxxxxxxxx> wrote: Quoting Allen Daves : > > > See attached 2 diagrams...Don't everyone get all up in a uproar if you > don't > > understand, then this may just be more info then you need. However, this > is > > for those few who think that since no "rotation" exist in the earths > orbit, > > therefore we could not observer or detect any kind of a rotational effects > > .....Regner appears to be such a fellow.. :-) > > > Correct! > I predict that if there is no rotation, we will observe no rotation! > > I believe your first figure depicts something like a bead on a curved wire. > That means the orientation of the bead follows the direction of the wire, > which means the bead will have rotated by about 180' between entering and > leaving your set-up. > The net movement if you start at the left, is a rotation by 180' clockwise > AND a translation from left to right. > > - Regner > > > > > > 1. I show you dont need any "rotataion" to observer a "rotaional effect" > as > > long as the net postions recorded are equivilent to the ones found in a > > rotaional motion. > > > > 2. I show that thoes certain nessiary conditons do exist for the earth > even > > in a "translated" motion of earth's orbit... > > > > The conditions are quite simple: > > A. A camera ( it does not matter if it is fixed year around or not for the > > very reasons i discuss here.) that is oriented parallel to any axis will > not > > be affected by any amount of latitude along that axis. > > B.As long as the camera is oriented radialy to any axis in question > > > > If those two conditions exist then in all cases the camera will record the > > net effects of a rotational motion. > > > > The point here is to show that there is no meaningful way ( certainly > > none as of yet demonstrated or explained) to assert that the earth orbits > the > > sun, even in a (translated orbit) and yet has no "net effect" of > "rotation" > > that could be observed meaningfully by an observer here on the earth.. > > > > > > > > I wonder if I'm gonna regret this as much as my gut tells me I will...LOL > > :-) > > > > > > > > > > > > > > Allen Daves wrote: > > > > Your a closet Geocentrist aren?t you? :-) > > > > > > Regner Trampedach wrote: Quoting Neville Jones : > > > > > > Dear Regner, > > > > > > The point of the two diagrams was that each illustrate two types of > > motion, > > > depending upon how you view them. > > > > > > In particular, the camera is always fixed to an immovable mount, and it > is > > > the World itself that moves. > > > > > > In Camera movement 2 negative.gif, attached again for your convenience, > we > > > have the essence of the two-axis argument. > > > > > > View it one way, and the optical axis of the camera always points toward > > the > > > celestial polar axis, > > > > > Which is not what the figure shows, but I assume you ask me to imagine the > > cameras pointed towards me (towards a celestial pole). > > > > > irrespective of the time increments. This explains what > > > we see, night after night, hour after hour, minute by minute, whether > > > sidereal or solar. > > > > > Again the figure shows increments of Solar days, but I'll imagine what > > happens on all time-scales. > > > > > View it another way and the optical axis always points > > > toward the ecliptic polar axis > > > > > No - it can't, because the two axes are not parallel. > > You drawing is a bit misleading in that way, as I pointed out before > > - the daily rotation occurs in a different plane from the yearly > > translational movement around the Sun. > > > > The Rotation on each axis is independent of the other axis we only need a/ > > any radial conditon around any/ either of the two axis to create star > > trails..How and why you think they need to take place in the same plane or > > the fact they don't take place in the same plane is somehow relevant for > what > > we should observe is somewhat baffling. > > > > > (with the proviso, of course, that we tilt the > > > paper, because the celestial and ecliptic axes are not coincident), > > > > > But with that tilt, you seem to imply that the equatorial plane suddenly > > aligns with the ecliptic plane - that is a pretty selective tilt. > > > > Again the rotation on both axis exist on two independent planes that > > intesect the observer on the earth. Never the less, and in any case, it > makes > > no difference! If there was no spin on the nightly axis the plane of the > > ecliptic would not change oreintaion nor would it affect the rotational > > conditon of either axis. The point here is that spin or no spin on the > > celestial axis is irrelevant for what takes place on the ecliptic axis. > The > > two motions do not depend nor are they capable of negating each other. > > > > I you have such powers, I might change profession :-) > > The cameras seem to be mounted on the Earth's equator (doesn't make > > any difference but makes for simpler explanation). > > With your figures and your explanations, the camera is then either > > pointing along > > a) the equatorial plane extending out from the Earth (as shown on > > your figure) or > > b) the axis of Earth's daily rotation = celestial axis, which > > by definition is just perpendicular to the plane of case a). > > When you tilt the paper, you also tilt the equatorial plane by the > > same amount - which means it doesn't change anything. > > > > With a camera on a fixed mount on Earth, with the camera pointed at a > > particular angle with respect to the celestial pole, the camera will > > only see that same great circle around the celestial pole. > > > > No a camera offset 23.44o to the celestial axis will alway be parallel to > > the ecliptic axis all day long. The key point you fail to appreciate > however, > > is that this conditon every 24 hours places the camera in the exact same > and > > thus defacto "rotational position" around the ecliptic axis every night > and > > over the course of a year. Even if you want to quible about the > termonology > > of "rotation", the fact is that in that position every 24 hours that > camera > > is in the exact same geometric configuration/ postion it would be if it > > "really" were in "rotation" no matter how you wish to define it. The plane > of > > the Rotaion is irrelevant. > > > > The movement recorded at fixed Solar time over a year, will be the > > same as that recorded over a single day, as I have stated before. > > > > That is what we see Yes, however, this does not explain why that is all we > > see. > > > > You can of course point your camera at the ecliptic pole and taking > > pictures every sidereal day you'll keep seeing the ecliptic pole. > > > > Yes every 23h 56 min you are correct! > > > > You'll in fact, see that same spot around the ecliptic pole, with > > the exact same orientation - it will not rotate during the year. > > > > That fact is not in dispute. What you have thus far failed to address is > > the condition of a camera on 24 hour intervals extending radialy and > parallel > > to the annual axis... (the same geometic configuration/ postion as would > > exist in a state of rotataion regaurdless of how you define "rotation" or > if > > "real roation" exist or not) > > > > At any other times, however, you'll see other parts of the great > > circle at 23.4' from the pole. > > The pole can, of course, be either the North or the South pole. > > > > > each24-mean-solar-hour step. > > > This explains what we should see (but do not), for > > > exactly the same reason. > > > > > It is a simple misunderstanding. > > > > > In the first viewing mode, the large circle is the World, with the > centre > > of > > > the World at the centre. In the second viewing mode, the small circles > > > represent individual positions of the World, with the large circle being > > the > > > World's alleged orbit and the centre of the diagram being the centre of > > the > > > Sun. (The slight eccentricity of the orbit is not relevant to this > > > discussion.) > > > > > Okay. > > > > > Note that the camera can be rotating about the celestial axis daily, but > > > still align its optical axis with the ecliptic polar axis at tropical > day > > > increments. > > > > > Exactly as I wrote above :-) > > > > > The only difference we should expect to see between the two sets > > > of star trails is that the annual ones would be only roughly circular. > > > > > But, this, I'm afraid, is where you err. As I also wrote above: > > "At any other times, however, you'll see other parts of the great > > circle at 23.4' from the pole." > > There will be no star trails around the ecliptic pole. > > > > Your stating your position eloquently and emphatically, but your not > > demonstrating the point, your merely asserting it. You assume this is > > true.You are in effect only explaining what we observe in reality. You are > > not addressing why we can't see the annual, ecept to say that since it is > not > > observable then it is there but only cannot be seen!? In so doing, you are > > ignoring the key issues (and the fact that somehow a smaller rotation is > > masking a much larger rotation but you can't explain why it is not the > larger > > one that is not masking the smaller one.) If you model this you will see > that > > what you describe is untenable and everything just as we have described > would > > in fact present secondary/annual star trails. A simple experiment with a > > camera and using the real celestial pole will demonstrate this for you. > You > > cannot have a transnational motion or any motion around a axis on a sphere > > and not have a point of rotation around that axis. > > Regards, > > > > Regner > > > > Dont worry i'll keep your secret..:-) > > > > Allen > > > > > Neville > > > www.GeocentricUniverse.com > > > > > > -----Original Message----- > > > From: art@xxxxxxxxxx > > > Sent: Wed, 14 Nov 2007 14:20:47 +1100 > > > > > > Quoting Neville Jones > > > > > > > > Regner, > > > > > > > > Thank you. And I accept your inference that the orbit, at this > > inclination, > > > > ought strictly to be elliptical. > > > > > > > Okay, so the axis perpendicular to the screen is the daily rotation axis > > > of the Earth, and the orbit of the Earth around the Sun should be > > > foreshortened > > > by the 23.4' angle between that axis and the ecliptic axis. > > > > > > > However, there is a second interpretation of the figure. That this > does > > not > > > > depict one camera, but 16 cameras scattered around the World, all with > > > their > > > > optical axes parallel with the celestial polar axis. > > > > > > > Okay - so all the cameras are pointed at the viewer of your figure? > > > And each of the 16 instances of Earth, has 16 cameras mounted, > > equidistantly > > > on the equator? > > > That is not a different view of the same thing - that's a different > > > scenario. > > > > > > > In this case, the time > > > > intervals, for rotation about the celestial polar axis (in the plane > of > > the > > > > paper/screen), can be sidereal or solar. Agreed? > > > > > > > The time intervals between the 16 instances of Earth that you depicted > in > > > your > > > two figures? They are obviously unaffected by where you put a > > camera...?... > > > I don't think I quite get your question. > > > > > > Regards, > > > > > > Regner > > > > > > > > > > > > > > > Get Free 5GB Email â?? 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