[geocentrism] Re: Tides and the moon and M-M

  • From: Allen Daves <allendaves@xxxxxxxxxxxxxx>
  • To: geocentrism@xxxxxxxxxxxxx
  • Date: Fri, 4 Apr 2008 16:22:35 -0700 (PDT)

Phil, There can be no  "differeing gravity foces." to accelerate the water 
upward if gravity pulls on everthing on the accelerometer (earth) at the same 
time in the same way such that it prevents a detectable acceleration in free 
fall....... !?

----- Original Message ----
From: philip madsen <pma15027@xxxxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Friday, April 4, 2008 4:08:42 PM
Subject: [geocentrism] Re: Tides and the moon and M-M

Thank you Peter.. You saved me from wondering how to explain the simple 
phenomena to them..  Because the water is fluid tidal flows can move under the 
differeing gravity foces. 
When the moon is overhead we weigh less because we are subject to two forces 
one up one down and the vector difference is positive down..  
Of course there will be a point somewhere between the bodies closer to the moon 
where the vector forces in each direction will be equal and a mass will have no 
weight. Go closer to the moon and it will fall to the moon  go closer to the 
earth and it will fall back to earth..  I would imagine this neutral position 
would be easier to maintain than the similar experience on a piece of iron 
between two magnets..  But even there, we can have a neutral position of zero 
force..  not zero magnetism..    to say zero gravity is a misnomer..  we mean 
zero force of gravity due to balancing forces.  
Its just a big hill actually.. If we had a real road to the moon, it would be 
uphill three quarters of the way, and down hill the rest of the way. 
Or again if you kick a ball straight up into the air there wil be a split 
second when it will have no weight,  this does not mean there was no gravity..  
----- Original Message ----- 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Saturday, April 05, 2008 6:06 AM
Subject: [geocentrism] Re: Tides and the moon and M-M

As you know, I have no scientific knowledge, but it seems logical to me that, 
rather than there being a "zero gravity point", that instead there is a point 
where the pull of gravity from the moon, is equal to the pull of gravity from 
the Earth, that is, the two forces pulling equaliy at a given point.
If you go nearer the moon, you still have the pull of gravity from the Earth, 
but it is less than the increasing pull from the moon, and visa versa.
Surely, if there was a point where gravity was zero, the moon would escape from 
its orbit?
Pete Charlton
----- Original Message ----- 
From: Bernie Brauer 
To: geocentrism@xxxxxxxxxxxxx 
Sent: Friday, April 04, 2008 12:04 AM
Subject: [geocentrism] Re: Tides and the moon and M-M

"It is widely accepted, although not by me, that the moon causes the tides. It 
is also widely accepted, although not by me, that there exists a zero-gravity 
point situated somewhere between the World and moon.
My question is this: If the ocean were situated at the zero-gravity point, then 
there would be no tide. Closer to the World the pull of the World is stronger. 
Closer to the moon the pull of the moon is stronger. The net effect, this side 
of the zero-gravity point, is always a positive pull by the World. Since this 
is equivalent to a force of gravity that produces a stronger pull as we take 
the oceans further this side of the zero-gravity point, then how does the moon 
produce the tides?"  Dr. Neville T. Jones
"IT DOES NOT DIRECTLY, ONLY INDIRECTLY. Hooray! Iʼm so glad finally someone 
else sees this issue too. Further, the tides are one of the major reasons why I 
model gravity as a vibration, for The Alias Effect shows that the position of 
the sun and moon has a relationship to gravity on Earth but tides demonstrate 
that they are not directly related due to the whole satellites issues as well 
as atmosphere. However, in vibrational gravity the positions of CB's ( 
Celestial Bodies ) will affect the vibrational wave. In short, the tides are 
caused by the squeezing effect of the gravity vibration, that is to say, that 
there is no additional or absence of gravity force, only a uneven squeezing 
effect that is a result in part due to sun/moon/background-stars positioning ( 
The Alias Effect proves this ). A vibration is the only known physical 
explanation that can account for that effect while producing a non-detectable 
gravity force in all of its anomalies, which
 are not anomalies but rather clear indicators that gravity is a vibration of 
aether waves. No other known physical construct could account for all those 
things."  Allen Daves

Jack Lewis <jack.lewis@xxxxxxxxxxxx> wrote:
I haven't yet seen anyone come with an answer to something Neville, I think, 
once said regarding the point, which must exist, between the Earth and the Moon 
where the gravity is zero. This being the case how is it that the Moon controls 
the tides? I'm sure, I think, that there must be a simple answer. 

The M-M part of the subject is to ask Regner how he is getting on with the 
answering the interferometer experiments wrt a non-moving Earth?


You rock. That's why Blockbuster's offering you one month of Blockbuster Total 
Access, No Cost.

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