[geocentrism] Re: Tides and the moon and M-M

  • From: "philip madsen" <pma15027@xxxxxxxxxxxxxx>
  • To: <geocentrism@xxxxxxxxxxxxx>
  • Date: Sat, 5 Apr 2008 17:36:02 +1000

Before I get kicked I realise my explanation was simplistic..WAVE propagation 
is a complex subject .  There are many misconception on the nature of the tides 
particularly on the internet.  I think the following gives a fairly good detail 
if you can cope with this rule , ITS DYNAMICALLY THE SAME FOR GEOCENTRISM OR 
HELIOCENTRISM even if different theoretical reasons need to be invoked. You can 
use the links directly from here if you want more detail. 

Tide
From Wikipedia, the free encyclopedia
Tides are the rising and falling of Earth's ocean surface caused by the tidal 
forces of the Moon and the Sun acting on the oceans. Tidal phenomena can occur 
in any object that is subjected to a gravitational field that varies in time 
and space, such as the Earth's land masses. (see Other tides).

Tides noticeably affect the depth of marine and estuarine water bodies and 
produce oscillating currents known as tidal streams, making prediction of tides 
very important for coastal navigation (see Tides and navigation). The strip of 
seashore that is submerged at high water and exposed at low water, the 
intertidal zone or foreshore, is an important ecological product of ocean tides 
(see Intertidal ecology).

The changing tide produced at a given location is the result of the changing 
positions of the Moon and Sun relative to the Earth coupled with the effects of 
Earth rotation and the local shape of the sea floor.[1] Sea level measured by 
coastal tide gauges may also be strongly affected by wind.

      Contents
      [hide]
        a.. 1 Introduction and tidal terminology 
          a.. 1.1 Tidal range variation: springs and neaps 
          b.. 1.2 Tidal phase and amplitude 
        b.. 2 Tidal physics 
          a.. 2.1 Tidal forces 
          b.. 2.2 Laplace tidal equation 
          c.. 2.3 Tidal amplitude and cycle time 
          d.. 2.4 Tidal dissipation 
        c.. 3 Tidal observation and prediction 
          a.. 3.1 Timing 
          b.. 3.2 Tidal analysis 
          c.. 3.3 Tidal Current 
          d.. 3.4 Tidal Power Generation 
        d.. 4 Tides and navigation 
        e.. 5 Biological aspects 
          a.. 5.1 Intertidal ecology 
          b.. 5.2 Biological rhythms and the tides 
        f.. 6 Other tides 
        g.. 7 Misapplications 
        h.. 8 See also 
        i.. 9 External links 
          a.. 9.1 Tide predictions 
        j.. 10 References and notes 
     

  ----- Original Message ----- 
  From: philip madsen 
  To: geocentrism@xxxxxxxxxxxxx 
  Sent: Saturday, April 05, 2008 4:51 PM
  Subject: [geocentrism] Re: Tides and the moon and M-M


  Allen the fact it took you 1000 plus words to convince us my simple 
explanation was wrong, shows how weak the ground is under your feet. 
  Logic states in your very first , your own answer.  But you cannot see it.  
Hence I am disenclined to read the rest. But I will as it is my happy hour. 
  1. If gravity in your model pushes then how on earth can the tides lag behind 
the moon ..if gravity pushes the tides the moon would push the tides not lag 
them behind!? 



  I said semantics does not matter.. Action is the same in either system 
theory. 



  First and foremost The moon does not pull the tides nor does it or anything 
else push it..  Hmm perhaps my "squeesze" was a bad choice. Water seeks its own 
level according to its head pressure at various parts, causing currents..  The 
head pressure is relative to gravity..  Level is also a bad choice, coz on a 
curved sphere of equal gravity the water level is a curve. 



  The lag of the water lift is for the same reason in mine or conventional 
gravity. There may be timedelay due to aether , speed of light limits what 
ever, but such is a negligible few seconds. The delay is purely fluid dynamics. 
in the direction of rotation,  whether its earth rotation shifting away from 
under the water, or rotation across the sky..  The effect shifts rather 
quickly, The water wave has to catch up.  And don't be confused.. The wave, 
action of the tide around the globe moves at a max of  1000 mph .  The water 
does not move around the globe at all..  Tidal curents are caused by 
depressions in the globes topological construction, such as channels estuaries, 
land masses rivers etc..  



  Philip. 





   

    ----- Original Message ----- 
    From: Allen Daves 
    To: geocentrism@xxxxxxxxxxxxx 
    Sent: Saturday, April 05, 2008 1:56 PM
    Subject: [geocentrism] Re: Tides and the moon and M-M


    Phil,

    How can this be so hard?.. I’m not arguing what you state in

    1. If gravity in your model pushes then how on earth can the tides lag 
behind the moon ..if gravity pushes the tides the moon would push the tides not 
lag them behind!?

     2.However, If gravity pull everything at the same time ( your attempted 
GTR explanation for why we can not detect the accelerations of grav in free 
fall) then it pulls the earth at the same time to the same degree...If it does 
not then you can't claim the acceleration is not detected..for crying out loud 
go to the beach and watch it...but then if you say that is the observable 
acceleration of earth in a free fall around the sun& moon then you cant claim 
the reason we cannot detect the earths acceleration around the sun because 
gravity is pulling everything all at the same time......!?

    You don't see that it is the GTR 's acceleration explanations that lost 
this whole argument before it began not me. You don't seem to fully 
understanding the GTR dynamics in the first place. However, neither I nor my 
"gravity" theory has any problems or inconsistencies with the tides and 
accelerations in a free fall.. GTR does...so which one is closer to the 
truth...?!........If inertial accelerations cannot be detected in free fall 
then how can the earths oceans demonstrate a physical and observable 
acceleration of the earth/ moon/ sun/ in free fall around one another’s 
gravitational field? There is no difference between the earth/ oceans and your 
accelerometers........... Both are simply mass suspended elastically( 
spring/hydrostatic force)!....Phill you missing the obvious ...... There is a 
difference the text book answers found in GTR  and the practical applications 
in the real world. 

    Yes we see tides they are real "in carnate"....the MS explanations for what 
causes them is not only just imagined but inconsistent with GTR's / your 
explanations for accelerations in a free fall ....You don’t seem to grasp the 
difference between reality (tides) and imagination (GTR accelerations)..? 
Reality and GTR are not compatible ....!?

    How gravity works does make a great deal of difference. Yes you still call 
it gravity but a push gravity does not function the same way a pull gravity is 
assumed.....It could, but observations such as the tides and the Allais effect 
demonstrate that it most certainly does not work the way MS gravity in a grav 
free fall  claims or attempts to explain how things work. It is much more then 
just  a "semantic theory". It gets to the very core of how things could or 
would work, which are not the same in the two theories! GTR cannot be the 
explanation for how things work...at least if logic and observations "have 
anything to do with the conclusions"....??? Tides demonstrate usfull 
information about gravity it is just not consistent with GTR's assertions! 

    3. The Allais effect demonstrates that the position of the moon with the 
sun do have a direct, (not just assumed delay… this is to say the tides and the 
moon/ sun do not correspond exactly and it is not even consistent) association 
with the tides.  Further, That direct relationship shows that gravity 
pushes.......well how can gravity push but cause the tides to lag behind rather 
then push ahead???????!!!!!

    The Answer is simple:
    A. Gravity does not work in any shape form or fashion as MS portrays it 
certainly not within GTR.

    B. The relationship between the moon/sun and tides is therefore related but 
only indirectly not directly. If it were direct then the push gravity of the 
moon would cause the tides to advance the moon/suns positions not lag....that 
is not the case...

    C. There is only one known possible "physical cause" and mechanical action 
that is capable of creating such a phenomena based on the locations of other 
objects within a given matrix.....and for other just as if not more powerful 
reasons that (i will not get into here) 

    The solution: The physical cause of gravity is a vibration in a 
"Homogeneous", "smooth" matrix (aether) with "non-indigenous" substances 
(ordinary matter) scattered throughout it.... The speed of light is only a 
limit for EMR because EMR are ultra high frequencies in a dense medium.....thus 
restricted just as in the case of various frequencies of light moving at 
differnet speeds through glass, air, water........Gravity is a very low 
frequency that traverses a very dense medium, the whole universe in somthing 
like -10^44 sec that is why it cannot be detected directly only its effects can 
be measured... instrumentations and the affects of aether waves on matter 
directly are only capable of demonstrating a effect at light speed at best but 
the force/wave itself prorogates faster then is possible to measure... our 
ability to measure it is limited to the speed of light...but there are other 
ways to ascertain it's "properties".....they are just very difficult....
    Viva "AVGM" (Aetheral Vibrational Gravitational Model).. (:-D)

    That is the very very short version..... 


    ----- Original Message ----
    From: philip madsen <pma15027@xxxxxxxxxxxxxx>
    To: geocentrism@xxxxxxxxxxxxx
    Sent: Friday, April 4, 2008 7:30:57 PM
    Subject: [geocentrism] Re: Tides and the moon and M-M


    Phil, There can be no  "differeing gravity foces." to accelerate the water 
upward if gravity pulls on everthing on the accelerometer ......Allen

    Allen, when the moon is dead centre over head the net or resultant of the 
two gravitational forces 180 degrees out of phase is less at that point than it 
is at any other phase angle either side of top dead centre.  That is what I 
meant by differing gravity, or varying gravity..  Water seeks a common level 
due to gravity.. It will flow from where there is no moon overhead to that area 
beneath the moon. 

    This is proven no matter which semantic theory you want to apply to 
gravity. 

    I say the gravity is aetheric push not molecular pull. But I still call it 
gravity. Its a very grave subject.  a matter of grave concern. I gravitate to 
my theory. Therefore if the aether over here squeezes all the water to over 
there under the moon, because the moon interfered with and caused a lower 
aether pressure or less gravity under the moon, then it is still all the same 
thing..  The moon caused the tides by being where it is.. 

    And don't try bringing this into it, "if gravity pulls on everthing on the 
accelerometer "  
    You lost that argument well and truely before you started it.. 

    Phil
      ----- Original Message ----- 
      From: Allen Daves 
      To: geocentrism@xxxxxxxxxxxxx 
      Sent: Saturday, April 05, 2008 9:22 AM
      Subject: [geocentrism] Re: Tides and the moon and M-M


      Phil, There can be no  "differeing gravity foces." to accelerate the 
water upward if gravity pulls on everthing on the accelerometer (earth) at the 
same time in the same way such that it prevents a detectable acceleration in 
free fall....... !?
       

      ----- Original Message ----
      From: philip madsen <pma15027@xxxxxxxxxxxxxx>
      To: geocentrism@xxxxxxxxxxxxx
      Sent: Friday, April 4, 2008 4:08:42 PM
      Subject: [geocentrism] Re: Tides and the moon and M-M


      Thank you Peter.. You saved me from wondering how to explain the simple 
phenomena to them..  Because the water is fluid tidal flows can move under the 
differeing gravity foces. 

      When the moon is overhead we weigh less because we are subject to two 
forces one up one down and the vector difference is positive down..  

      Of course there will be a point somewhere between the bodies closer to 
the moon where the vector forces in each direction will be equal and a mass 
will have no weight. Go closer to the moon and it will fall to the moon  go 
closer to the earth and it will fall back to earth..  I would imagine this 
neutral position would be easier to maintain than the similar experience on a 
piece of iron between two magnets..  But even there, we can have a neutral 
position of zero force..  not zero magnetism..    to say zero gravity is a 
misnomer..  we mean zero force of gravity due to balancing forces.  

      Its just a big hill actually.. If we had a real road to the moon, it 
would be uphill three quarters of the way, and down hill the rest of the way. 

      Or again if you kick a ball straight up into the air there wil be a split 
second when it will have no weight,  this does not mean there was no gravity..  

      Philip. 
        ----- Original Message ----- 
        From: PETER CHARLTON 
        To: geocentrism@xxxxxxxxxxxxx 
        Sent: Saturday, April 05, 2008 6:06 AM
        Subject: [geocentrism] Re: Tides and the moon and M-M


        As you know, I have no scientific knowledge, but it seems logical to me 
that, rather than there being a "zero gravity point", that instead there is a 
point where the pull of gravity from the moon, is equal to the pull of gravity 
from the Earth, that is, the two forces pulling equaliy at a given point.

        If you go nearer the moon, you still have the pull of gravity from the 
Earth, but it is less than the increasing pull from the moon, and visa versa.

        Surely, if there was a point where gravity was zero, the moon would 
escape from its orbit?

        Pete Charlton
          
          ----- Original Message ----- 
          From: Bernie Brauer 
          To: geocentrism@xxxxxxxxxxxxx 
          Sent: Friday, April 04, 2008 12:04 AM
          Subject: [geocentrism] Re: Tides and the moon and M-M


          Statement/Question:
          "It is widely accepted, although not by me, that the moon causes the 
tides. It is also widely accepted, although not by me, that there exists a 
zero-gravity point situated somewhere between the World and moon.
          My question is this: If the ocean were situated at the zero-gravity 
point, then there would be no tide. Closer to the World the pull of the World 
is stronger. Closer to the moon the pull of the moon is stronger. The net 
effect, this side of the zero-gravity point, is always a positive pull by the 
World. Since this is equivalent to a force of gravity that produces a stronger 
pull as we take the oceans further this side of the zero-gravity point, then 
how does the moon produce the tides?"  Dr. Neville T. Jones
          Response:
          "IT DOES NOT DIRECTLY, ONLY INDIRECTLY. Hooray! I’m so glad finally 
someone else sees this issue too. Further, the tides are one of the major 
reasons why I model gravity as a vibration, for The Alias Effect shows that the 
position of the sun and moon has a relationship to gravity on Earth but tides 
demonstrate that they are not directly related due to the whole satellites 
issues as well as atmosphere. However, in vibrational gravity the positions of 
CB's ( Celestial Bodies ) will affect the vibrational wave. In short, the tides 
are caused by the squeezing effect of the gravity vibration, that is to say, 
that there is no additional or absence of gravity force, only a uneven 
squeezing effect that is a result in part due to sun/moon/background-stars 
positioning ( The Alias Effect proves this ). A vibration is the only known 
physical explanation that can account for that effect while producing a 
non-detectable gravity force in all of its anomalies, which are not anomalies 
but rather clear indicators that gravity is a vibration of aether waves. No 
other known physical construct could account for all those things."  Allen Daves

          Jack Lewis <jack.lewis@xxxxxxxxxxxx> wrote:
            I haven't yet seen anyone come with an answer to something Neville, 
I think, once said regarding the point, which must exist, between the Earth and 
the Moon where the gravity is zero. This being the case how is it that the Moon 
controls the tides? I'm sure, I think, that there must be a simple answer. 

            The M-M part of the subject is to ask Regner how he is getting on 
with the answering the interferometer experiments wrt a non-moving Earth?

            Jack 





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