[geocentrism] Re: Tides
- From: Paul Deema <paul_deema@xxxxxxxxxxx>
- To: geocentrism@xxxxxxxxxxxxx
- Date: Wed, 7 May 2008 20:47:57 +0000 (GMT)
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... I will ask a question to everyone.....if i am on a planet of one earth
mass that is falling toward the sun will i have any weight and how much will i
weigh and why?.....
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I believe I agree with Neville.
I make the assumption however that the path is a direct, straight line path.
Paul D
----- Original Message ----
From: Neville Jones <njones@xxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Wednesday, 7 May, 2008 8:17:39 PM
Subject: [geocentrism] Re: Tides
-----Original Message-----
From: allendaves@xxxxxxxxxxxxxx
Sent: Wed, 7 May 2008 08:14:47 -0700 (PDT)
Your weight is a force and is therefore given by Newton's F=ma, where m is your
mass (in kg for example) and a is the acceleration (m/s/s) produced by this
force.
There will be a force acting on you directed towards the centre of the World,
where the acceleration resulting from this force at the World's surface is g
m/s/s. And there will be a force acting on you and directed towards the centre
of mass of the Sun, where the acceleration due to this at the World's surface
is g' m/s/s. These will be acting in opposite senses.
Your weight, W, will therefore be
W = mg - mg' = m(g - g') N
and will act towards the centre of the World until such time (since the World
is in 'free fall' towards the Sun) as g' = g, when you will become weightless.
Then, as g' > g, you will be pulled off the World and fall into the Sun before
the World does. I.e., your weight would be constantly changing.
The above assumes that you are positioned on the same side of the World as the
Sun and that you are not an 'extended' object, at least not in relation to the
strength (size) of the gravitational field of either the World or the Sun.
Neville.
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