*From*: "Ron Leach" <rleach@xxxxxxxxxxxxxxx>*To*: <windows2000@xxxxxxxxxxxxx>*Date*: Wed, 29 Nov 2006 10:23:44 -0500

Only 13 years?!? Try 22 years ;-). I'm thinking that this might be a start... 1/2(e^x + e^-x) =4 ln (e^x + e^-x)^1/2 = ln 4 ln sqrt (e^x + e^-x) = ln 4 but now where to go... -----Original Message----- From: windows2000-bounce@xxxxxxxxxxxxx [mailto:windows2000-bounce@xxxxxxxxxxxxx] On Behalf Of Costanzo, Ray Sent: Wednesday, November 29, 2006 9:51 AM To: windows2000@xxxxxxxxxxxxx Subject: [windows2000] Re: OT - Math Question There is not a chance in hell I could ever do this. It's depressing. Take me back to high school and I think I could do it. Now, 13 years later, I don't have a clue where to begin. I briefly discussed it with my brother who said: <quote> I don't have time to look at it right now, but my first thought would be to use the natural log function to pull x out of the exponent. Example: e^x = 4 ln(e^x) = ln(4) x(ln(e)) = ln(4) x = ln(4) Your equation may not be so easy, because you'll have ln(e^x + e^-x), so you can't just move the x out of the exponent. </quote> Ray at work -----Original Message----- From: Ron Leach It's been a long while in doing the math problems, so please pardon the OT. I was wondering if anyone would be able to help with the following math problem (a little break from the normal stuff :-)) 1/2(e^x + e^-x) = 4, solve for x. Thanks! Ron PS Maybe Jim has a math list? ;-) ***************************** New Site from The Kenzig Group! Windows Vista Links, list options and info are available at: http://www.VistaPop.com ***************************** To Unsubscribe, set digest or vacation mode or view archives use the below link. http://thethin.net/win2000list.cfm ***************************** New Site from The Kenzig Group! Windows Vista Links, list options and info are available at: http://www.VistaPop.com ***************************** To Unsubscribe, set digest or vacation mode or view archives use the below link. http://thethin.net/win2000list.cfm

**References**:**[windows2000] Re: OT - Math Question***From:*Costanzo, Ray

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