*From*: Chris Berry <chris_berry-list-windows2000@xxxxxxxxxxxxxxxxx>*To*: windows2000@xxxxxxxxxxxxx*Date*: Wed, 29 Nov 2006 13:25:24 -0800

Moby wrote:

Chris Berry wrote:Mark Lane wrote:I was a math major in a former life 10+ years. 1/2(e^x + e^-x) = 4 e^x + e^-x = 8 (e^x)^2 + 1 = 8e^x Let y = e^x such that x = ln(y). y^2 + 1 = 8y y^2 - 8y + 1 = 0Use quadratic formula, which is x = (-b +- sqrt(b^2 - 4ac))/2a, tosolve fory in previous equation. Then x = ln(y)Pretty, but pure handwaving, you still didn't provide a value for x.To continue the handwaving some more then :)Using the quadratic formula and keeping only the positive value for y (y= e^x - as such y cannot be negative!) we get:y = (8 + 9.592) /2 = 8.796 This means e^x = 8.796 => x = ln(8.796) = 2.174

I used: =1/2*(2.71828183^A1+2.71828183^(A1*-1)) and got 4.4536 not 4 I'm a little rusty though, did I miss something? -- Chris Berry chris_berry@xxxxxxxxxxxxxxxxx Information Advisory Manager JM Associates

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**Follow-Ups**:**[windows2000] Re: OT - Math Question***From:*Moby

**References**:**[windows2000] Re: OT - Math Question***From:*Mark Lane

**[windows2000] Re: OT - Math Question***From:*Chris Berry

**[windows2000] Re: OT - Math Question***From:*Moby

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