[SI-LIST] Re: high-order coupling between inductors in hspice
- From: Zhangkun <zhang_kun@xxxxxxxxxx>
- To: Tracy.Barclay@xxxxxxxxxxxx
- Date: Tue, 26 Oct 2004 09:20:46 +0800
Tracy
If there are more than three inductors, is the automatic calculation of
couplint still right?
In another word, I do not turn off the calculation of second order coupling.
There are five inductor L1, L2, L3, L4, L5. There are coupling between every
two conductor. After I added the coupling between (L1, L2), (L2, L3), (L3, L4),
(L4, L5), should I still add the other coupling, such as that between (L1, L3),
(L1, L4), (L1, L5), (L2, L4), (L2, L5), (L3, L5)?
Best Regards
Zhangkun
2004.10.26
----- Original Message -----
From: "Tracy Barclay" <Tracy.Barclay@xxxxxxxxxxxx>
To: <zhang_kun@xxxxxxxxxx>
Cc: <si-list@xxxxxxxxxxxxx>
Sent: Tuesday, October 26, 2004 7:59 AM
Subject: [SI-LIST] Re: high-order coupling between inductors in hspice
> Hi Zhangkun,
>
> If you want to turn off the calculation of second order coupling, set
>
> .option genk=0
>
> in your netlist.
>
> Tracy Barclay
> CAE
> Synopsys, Inc.
>
>
>
> -----Original Message-----
> From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On
> Behalf Of zhangkun 29902
> Sent: Monday, October 25, 2004 16:28
> To: Ray Anderson
> Cc: si-list@xxxxxxxxxxxxx
> Subject: [SI-LIST] Re: high-order coupling between inductors in hspice
>
>
> Ray
>
> I have use matrix method to check the automatic calculation. The following
> is my netlist.
>
> V1 node1 gnd ac 1
>
> L1 node1 node2 10mh
> L2 gnd node4 8.1mh
> L3 gnd node6 6.4mh
>
> K1 L1 L2 0.9
> K2 L2 L3 0.8888888888
> K3 L1 L3 0.8
>
> R1 node2 gnd 50k
> R2 node4 gnd 100k
> R3 node6 gnd 100k
>
> The current in V1 is simulated. When there is "K3 L1 L3 0.8", the
> simulation result is not correct. When "K3 L1 L3 0.8" is cut, the
> simulation result agree with that calculated by means of matrix method and
> is correct.
>
> As you have pointed out, it is dangerous. I agree with you. However, in the
> simulation, if there are second-order or higher-order coupling, how to do?
> Is it a bug in the tools?
>
> Best Regards
>
> Zhangkun
> 2004.10.26
>
> ----- Original Message -----
> From: Ray Anderson <reanderson@xxxxxxxxxxxxx>
> Date: Monday, October 25, 2004 11:08 pm
> Subject: Re: [SI-LIST] Re: high-order coupling between inductors in hspice
>
> > .
> >
> > >
> > >Warning: The automatic inductance calculation is only an
> > estimation and is
> > >accurate for a subset of geometries. The second-order coupling
> > >coefficient is simply the product of the two first-order
> > coefficients,>which is not correct for many geometries.
> > >
> > >
> > As it says: "which is not correct for many geometries"
> >
> > I think Andy's example of L1 and L2 close and L3 far falls into
> > that
> > category. It sounds to me that the auto-calc feature described in
> > the
> > manual is dangerous at best.
> >
> > -Ray Anderson
> >
> >
> >
> >
> >
> >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> >
> >
>
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