[SI-LIST] Re: high-order coupling between inductors in hspice
- From: zhangkun 29902 <zhang_kun@xxxxxxxxxx>
- To: Ray Anderson <reanderson@xxxxxxxxxxxxx>
- Date: Tue, 26 Oct 2004 07:27:36 +0800
Ray
I have use matrix method to check the automatic calculation. The following is
my netlist.
V1 node1 gnd ac 1
L1 node1 node2 10mh
L2 gnd node4 8.1mh
L3 gnd node6 6.4mh
K1 L1 L2 0.9
K2 L2 L3 0.8888888888
K3 L1 L3 0.8
R1 node2 gnd 50k
R2 node4 gnd 100k
R3 node6 gnd 100k
The current in V1 is simulated. When there is "K3 L1 L3 0.8", the
simulation result is not correct. When "K3 L1 L3 0.8" is cut, the
simulation result agree with that calculated by means of matrix method and is
correct.
As you have pointed out, it is dangerous. I agree with you. However, in the
simulation, if there are second-order or higher-order coupling, how to do? Is
it a bug in the tools?
Best Regards
Zhangkun
2004.10.26
----- Original Message -----
From: Ray Anderson <reanderson@xxxxxxxxxxxxx>
Date: Monday, October 25, 2004 11:08 pm
Subject: Re: [SI-LIST] Re: high-order coupling between inductors in hspice
> .
>
> >
> >Warning: The automatic inductance calculation is only an
> estimation and is
> >accurate for a subset of geometries. The second-order coupling
> >coefficient is simply the product of the two first-order
> coefficients,>which is not correct for many geometries.
> >
> >
> As it says: "which is not correct for many geometries"
>
> I think Andy's example of L1 and L2 close and L3 far falls into
> that
> category. It sounds to me that the auto-calc feature described in
> the
> manual is dangerous at best.
>
> -Ray Anderson
>
>
>
>
>
>
> >
> >
> >
> >
> >
> >
> >
>
>
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