[SI-LIST] high-order coupling between inductors in hspice
- From: Zhangkun <zhang_kun@xxxxxxxxxx>
- To: si-list <si-list@xxxxxxxxxxxxx>
- Date: Mon, 25 Oct 2004 18:29:35 +0800
Dear all
I have a question about high-order coupling between inductors in hspice. In
hspice manual, it is described that the second order coupling between inductors
could be automatically calculated. For example, there is L1, L2 and L3. The
coupling between L1 and L2, L2 and L3, is K1 and K2 respectively. The coupling
K3 between L1 and L3 could be automatically calculated as K3=K1*K2.
My question is that if there are more than three inductor, the calculation is
still OK or not. For example, there is four inductor, L1, L2, L3, and L4. Could
I only express the coupling between L1 and L2, L2 and L3, L3 and L4? I have
made a simple circuit to check. The result of hspice and matlat agree to each
other. However, I am still not sure about that. In the manual, this kind of
situation is not described. Please give me some advice.
Best Regards
Zhangkun
2004.10.25
------------------------------------------------------------------
To unsubscribe from si-list:
si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field
or to administer your membership from a web page, go to:
//www.freelists.org/webpage/si-list
For help:
si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field
List FAQ wiki page is located at:
http://si-list.org/wiki/wiki.pl?Si-List_FAQ
List technical documents are available at:
http://www.si-list.org
List archives are viewable at:
//www.freelists.org/archives/si-list
or at our remote archives:
http://groups.yahoo.com/group/si-list/messages
Old (prior to June 6, 2001) list archives are viewable at:
http://www.qsl.net/wb6tpu
Other related posts:
