[geocentrism] Re: Moving Earth Deception
- From: Robert Bennett <robert.bennett@xxxxxxx>
- To: geocentrism@xxxxxxxxxxxxx
- Date: Tue, 31 Jul 2007 23:32:08 -0400
2. Once a beam is transmitted, it travels in a straight line,
independent of any forces whatsoever. This means the beam as such during its
travel time is stationary in space. Its path is a fixed and stationary true
straight line from the earth, provided the transmitter is stationary.
[Robert Bennett] and so is the aether....
3. To make the movement of the transmitter irrelevant and relatively
stationary, or independent of any alleged rotation of the earth or its
orbital speed around the sun we must make the beam have no more than a few,
nominated
[Robert Bennett] = nominal ?
10 milliseconds of duration.
4. We need to know how wide the laser beam will be by the time it
reaches the moon. What size spot will it make. NASA's beam was 2km across.
Only one in 30 million photons were reflected from their reflector array. se
pic below . Another said:When pointing a well focussed laser at the moon,
its beam will widen to well over 100 meters in radius by the time it reaches
the surface.
5. For our purpose we need to shoot during a new moon to make the
flash/spot more visible.
[Robert Bennett] You would need all the lasers in the world to do this,
mate
We can use a killer laser to make sure it is visible. Telescope and
camera.
6. As we have effectively stopped any rotation of the earth by using
only a few milliseconds, we can assume the moon to be travelling radially,
[Robert Bennett] you surely mean tangentially/angularly....
as observed, for aiming purposes. (We are not measuring reflection
times, but visible patterns on the surface) [Robert Bennett] see 5
[Robert Bennett] ?? The NASA LLR exp measured reflection direction and
time
7. The reality of the moons speed will be proven because we are
making a comparison of the light pattern drawn on the moon
[Robert Bennett] see 5
by a truly stationary 10ms beam in space, with either a moon
travelling daily at 168,000mph or travelling monthly at 5,680mph in space.
8. It should be a simple calculation to compare the distance the beam
moves across the moonscape in 10milliseconds at either speed.
[Robert Bennett] can't be done with a single retro-reflector - the NASA
set-up
9. If the firing was done on a trajectory that was at right angles to
the forward motion of the earth around the sun, then again considering the
absolute stationary property of our light beam, during the time of our 1
second journey , both the moon and earth travelling at 30km/sec. will have
moved forward 30km. from the firing line. (no pun) by the time it marks the
moon.
[Robert Bennett] This is the key to understanding the import of the
NASA LLR results.
It's impossible for Earth and Moon to exchange light beams using a
single reflector that always returns the echo in the same direction as
received...... if they are moving parallel to each other .
If the Earth is motionless, it is not only possible, but actual, as
shown by NASA and stated in my original post and in GWW.
It is possible to receive the echo with intelligent aiming from Earth
(leading the target) and from the Moon (aberration correction) . But the
Moon reflector was not programmed.
10. From (9) then the spot will hit the moon 30 km behind where it
would hit during an inline with the earths orbit shot, 90 degrees of moon
orbit earlier. Also the 10ms beam will have a more elongated oval shape.
[Robert Bennett] Yes, If NASA could see and aim the laser directly at the
reflector, the beam would miss the Moon by ~ 30 km.
I look forward to any comments.
[Robert Bennett] You don't need to do your exp, requiring at least 2
visible detectors on the Moon.
NASA has already shown the Earth is geostatic. They - and the world -
just don't know it yet.
Did you draw the graphic below? Cool, Phul.
One nit: the outbound laser beam diverges much more than shown==> beam
width much larger than the reflector
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