Yes, I tried it both ways. I have found, though, that not using eval() causes 1+3 to equal 13, while using eval() gives me 4, which is the type of answer I am looking for.
Have a great day, Alex
----- Original Message ----- From: "Jeffrey Fidler" <jfiddler2@xxxxxxxxxxx To: <programmingblind@xxxxxxxxxxxxx Date sent: Wed, 6 Feb 2008 22:32:08 -0500 Subject: Re: a quick js code question
Alex,
eval() will evaluate a string argument. Did you try to just use
the
assignment operator to initialize your variable? i.e. var x = form.in.value;
HTH!
- Jeff
----- Original Message ----- From: "Alex Hall" <mehgcap@xxxxxxx To: <programmingblind@xxxxxxxxxxxxx Sent: Wednesday, February 06, 2008 10:08 PM Subject: a quick js code question
Hi all,I have a very simple program that, for some reason refuses to
run. I have
this function being called by a button and that part works, but
I cannot
get an answer out of this function. It seems to stop at where I
declare x
as a variable. The code, all 12 lines of it, is below. If
anyone can
point out what I know must be a very simple error I would really appreciate it. function eq(){ try{ x=eval(form.in.value); ans=(x-2)/(x*x)-4; form.out.value=ans;
catch(err){ alert(err+": "+err.description);
Have a great day, Alex __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind
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