Re: a quick js code question
- From: "Jeffrey Fidler" <jfiddler2@xxxxxxxxxxx>
- To: <programmingblind@xxxxxxxxxxxxx>
- Date: Wed, 6 Feb 2008 22:32:08 -0500
Alex,
eval() will evaluate a string argument. Did you try to just use the
assignment operator to initialize your variable? i.e. var x =
form.in.value;
HTH!
- Jeff
----- Original Message -----
From: "Alex Hall" <mehgcap@xxxxxxx>
To: <programmingblind@xxxxxxxxxxxxx>
Sent: Wednesday, February 06, 2008 10:08 PM
Subject: a quick js code question
Hi all,
I have a very simple program that, for some reason refuses to run. I have
this function being called by a button and that part works, but I cannot
get an answer out of this function. It seems to stop at where I declare x
as a variable. The code, all 12 lines of it, is below. If anyone can
point out what I know must be a very simple error I would really
appreciate it.
function eq(){
try{
x=eval(form.in.value);
ans=(x-2)/(x*x)-4;
form.out.value=ans;
catch(err){
alert(err+": "+err.description);
Have a great day,
Alex
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