Dear all: It's me again. Thanks Steve first to provide us good explanation of our = last question.... We then come out another one that in crosstalk calculation, why the = trace width does not be counted in.. For example, in Dr. Howard Johnson's first book page 192, there wrote: Crosstalk ~ K / (1 + (D/H)*(D/H)), where D: distance between two traces = center to center. H: height above the reference plane In real application, a pattern of 4.5/15 (trace width 4.5 and space 15) = will really have larger crosstalk than 5/15? (say the H is 4.1mil) Best regards! Allen Wang ASUSTeK Computer Inc. RD8- server centric division Manager Mobile: 886-935481831 TEL: 886-2-28943447 ext:3102 FAX: 886-2-28907689 ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu