RE: again a newbee question

  • From: "Ken Perry" <whistler@xxxxxxxxxxxxx>
  • To: <programmingblind@xxxxxxxxxxxxx>
  • Date: Wed, 13 Apr 2011 21:25:31 -0400

Nod you will not need things like scanf and getch and things of the like
when you get into serious coding because you will be probably building
windows apps of some kind and the window will remain open till you call
exit.  This is just while you're learning so feel free to use scanf, getch,
getchar, or any of the things like read to just hold the program till your
ready to close.

Ken

-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of ashish rohtagi
Sent: Wednesday, April 13, 2011 9:05 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: Re: again a newbee question

sorry, I corrected the mistake about printf and scanf. thanks for the
advice. take care, regards. ashish

On 4/14/11, Littlefield, Tyler <tyler@xxxxxxxxxxxxx> wrote:
> I'm sorry, getch should be getchar. Also: it's fairly bad coding style
> to put a printf on the same line as a scanf. Unless you have good
> reason, try to keep your code separated. It makes it easier to read and
> people don't miss things quite as easily.
> On 4/13/2011 6:50 PM, ashish rohtagi wrote:
>> like this?? #include<stdio.h>
>>
>> int main()
>> {
>> char me[20];
>>
>>
>>
>> printf("What is your name?"); scanf("%s",&me);
>> printf("Darn glad to meet you, %s!\n",me);
>>
>> scanf("s%",&me);
>>
>> return(0);
>> } but result is still the same. can I use getch fungtion? if yes
>> please tell me how to use it . take care, regards.
>>
>>
>> On 4/14/11, Jared Wright<wright.jaredm@xxxxxxxxx>  wrote:
>>> It goes right between the last printf statement and the return
>>> statement. It's job is to hold the program open at the end, so it should
>>> be the last statement before return, which ends the program.
>>> On 4/13/2011 12:09 PM, ashish rohtagi wrote:
>>>> hi Tyler, thanks for your suggestion, but I am unable to understand
>>>> where to put second scanf. will you just once show me? take care,
>>>> regards. ashish
>>>>
>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>   wrote:
>>>>> Like ken said, use scanf to catch it before the window closes, or run
>>>>> it
>>>>> in a command line. Here's what's happening:
>>>>> You open the process, and the first scanf call blocks; that is to say,
>>>>> it will not process anything, it is simply waiting for the user to
>>>>> input
>>>>> something. But after it's done printing, there is no reason why it
>>>>> should stay open because you don't tell it to. So run from the command
>>>>> prompt, use getch() to let you hit enter before it closes or use
>>>>> another
>>>>> scanf.
>>>>> On 4/13/2011 9:32 AM, ashish rohtagi wrote:
>>>>>> friends, thanks for all the  encouragement. here is my problem, I
want
>>>>>> to use scanf fungtion. in input and output but as soon as I give my
>>>>>> input and press enter the window disappears. it does not give output
>>>>>> based on my input. here is the code. #include<stdio.h>
>>>>>>
>>>>>> int main()
>>>>>> {
>>>>>> char me[20];
>>>>>>
>>>>>> printf("What is your name?"); scanf("%s",&me);
>>>>>> printf("Glad to meet you, %s!\n",me); return(0);
>>>>>> }
>>>>>>
>>>>>>
>>>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>    wrote:
>>>>>>> O. oops. In my defense, I haven't found coffee. :)
>>>>>>> On 4/13/2011 7:46 AM, Jared Wright wrote:
>>>>>>>> It's there, just on the same line as the printf statement.
>>>>>>>> On 4/13/2011 9:35 AM, Littlefield, Tyler wrote:
>>>>>>>>> good job on using int main, just don't forget a return 0; when you
>>>>>>>>> are
>>>>>>>>> done. between the printf and the closing brace.
>>>>>>>>> On 4/13/2011 6:36 AM, ashish rohtagi wrote:
>>>>>>>>>> here is my code it compiles correctly but text just shows on the
>>>>>>>>>> screen for 1 second, I want it to stay. #include<stdio.h>
>>>>>>>>>>
>>>>>>>>>> int main()
>>>>>>>>>> {
>>>>>>>>>> printf("I will learn programming!\n"); return(0);
>>>>>>>>>> }
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On 4/13/11, DaShiell, Jude T. CIV NAVAIR 1490, 1, 26
>>>>>>>>>> <jude.dashiell@xxxxxxxx>    wrote:
>>>>>>>>>>> You didn't put your printf statement in your message, but let me
>>>>>>>>>>> make a
>>>>>>>>>>> guess. You didn't put a (\n) in before the closing quote mark so
>>>>>>>>>>> you
>>>>>>>>>>> just put text on the screen without a line ending. That could be
>>>>>>>>>>> one
>>>>>>>>>>> contributing factor. Another might be you didn't put an #include
>>>>>>>>>>> <stdio.h>    statement in at the top of your program and maybe
>>>>>>>>>>> used
>>>>>>>>>>> #include<conio.h>. If that's the case, don't use printf with
>>>>>>>>>>> conio.h
>>>>>>>>>>> unless you also include stdio.h. For conio.h, cprintf is the
>>>>>>>>>>> function
>>>>>>>>>>> you want. Hope this helps.
>>>>>>>>>>>
>>>>>>>>>>> -----Original Message-----
>>>>>>>>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>>>>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of
>>>>>>>>>>> ashish
>>>>>>>>>>> rohtagi
>>>>>>>>>>> Sent: Wednesday, April 13, 2011 8:04
>>>>>>>>>>> To: programmingblind@xxxxxxxxxxxxx
>>>>>>>>>>> Cc: punitdiwan@xxxxxxxxx
>>>>>>>>>>> Subject: again a newbee question
>>>>>>>>>>>
>>>>>>>>>>> friends, sorry here I am with another foolish question, sorry
but
>>>>>>>>>>> here
>>>>>>>>>>> is no one to teach and I am learning myself. when I print any
>>>>>>>>>>> text
>>>>>>>>>>> on
>>>>>>>>>>> screen using printf it quickly disappears. what should I do that
>>>>>>>>>>> it
>>>>>>>>>>> should stay? take care, regards. ashish
>>>>>>>>>>> __________
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>>>>>>> --
>>>>>>>
>>>>>>> Thanks,
>>>>>>> Ty
>>>>>>>
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>>>>> Thanks,
>>>>> Ty
>>>>>
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>
>
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>
> Thanks,
> Ty
>
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