Re: again a newbee question

  • From: ashish rohtagi <ashishrohtagi1969@xxxxxxxxx>
  • To: programmingblind@xxxxxxxxxxxxx
  • Date: Thu, 14 Apr 2011 06:40:37 +0530

hi Ken, you are god!  it worked like a charm! thanks. now please tell
me how to use getchar? take care,  regards. ashish

On 4/14/11, ashish rohtagi <ashishrohtagi1969@xxxxxxxxx> wrote:
> sorry, I corrected the mistake about printf and scanf. thanks for the
> advice. take care, regards. ashish
>
> On 4/14/11, Littlefield, Tyler <tyler@xxxxxxxxxxxxx> wrote:
>> I'm sorry, getch should be getchar. Also: it's fairly bad coding style
>> to put a printf on the same line as a scanf. Unless you have good
>> reason, try to keep your code separated. It makes it easier to read and
>> people don't miss things quite as easily.
>> On 4/13/2011 6:50 PM, ashish rohtagi wrote:
>>> like this?? #include<stdio.h>
>>>
>>> int main()
>>> {
>>> char me[20];
>>>
>>>
>>>
>>> printf("What is your name?"); scanf("%s",&me);
>>> printf("Darn glad to meet you, %s!\n",me);
>>>
>>> scanf("s%",&me);
>>>
>>> return(0);
>>> } but result is still the same. can I use getch fungtion? if yes
>>> please tell me how to use it . take care, regards.
>>>
>>>
>>> On 4/14/11, Jared Wright<wright.jaredm@xxxxxxxxx>  wrote:
>>>> It goes right between the last printf statement and the return
>>>> statement. It's job is to hold the program open at the end, so it
>>>> should
>>>> be the last statement before return, which ends the program.
>>>> On 4/13/2011 12:09 PM, ashish rohtagi wrote:
>>>>> hi Tyler, thanks for your suggestion, but I am unable to understand
>>>>> where to put second scanf. will you just once show me? take care,
>>>>> regards. ashish
>>>>>
>>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>   wrote:
>>>>>> Like ken said, use scanf to catch it before the window closes, or run
>>>>>> it
>>>>>> in a command line. Here's what's happening:
>>>>>> You open the process, and the first scanf call blocks; that is to
>>>>>> say,
>>>>>> it will not process anything, it is simply waiting for the user to
>>>>>> input
>>>>>> something. But after it's done printing, there is no reason why it
>>>>>> should stay open because you don't tell it to. So run from the
>>>>>> command
>>>>>> prompt, use getch() to let you hit enter before it closes or use
>>>>>> another
>>>>>> scanf.
>>>>>> On 4/13/2011 9:32 AM, ashish rohtagi wrote:
>>>>>>> friends, thanks for all the  encouragement. here is my problem, I
>>>>>>> want
>>>>>>> to use scanf fungtion. in input and output but as soon as I give my
>>>>>>> input and press enter the window disappears. it does not give output
>>>>>>> based on my input. here is the code. #include<stdio.h>
>>>>>>>
>>>>>>> int main()
>>>>>>> {
>>>>>>> char me[20];
>>>>>>>
>>>>>>> printf("What is your name?"); scanf("%s",&me);
>>>>>>> printf("Glad to meet you, %s!\n",me); return(0);
>>>>>>> }
>>>>>>>
>>>>>>>
>>>>>>> On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx>    wrote:
>>>>>>>> O. oops. In my defense, I haven't found coffee. :)
>>>>>>>> On 4/13/2011 7:46 AM, Jared Wright wrote:
>>>>>>>>> It's there, just on the same line as the printf statement.
>>>>>>>>> On 4/13/2011 9:35 AM, Littlefield, Tyler wrote:
>>>>>>>>>> good job on using int main, just don't forget a return 0; when
>>>>>>>>>> you
>>>>>>>>>> are
>>>>>>>>>> done. between the printf and the closing brace.
>>>>>>>>>> On 4/13/2011 6:36 AM, ashish rohtagi wrote:
>>>>>>>>>>> here is my code it compiles correctly but text just shows on the
>>>>>>>>>>> screen for 1 second, I want it to stay. #include<stdio.h>
>>>>>>>>>>>
>>>>>>>>>>> int main()
>>>>>>>>>>> {
>>>>>>>>>>> printf("I will learn programming!\n"); return(0);
>>>>>>>>>>> }
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On 4/13/11, DaShiell, Jude T. CIV NAVAIR 1490, 1, 26
>>>>>>>>>>> <jude.dashiell@xxxxxxxx>    wrote:
>>>>>>>>>>>> You didn't put your printf statement in your message, but let
>>>>>>>>>>>> me
>>>>>>>>>>>> make a
>>>>>>>>>>>> guess. You didn't put a (\n) in before the closing quote mark
>>>>>>>>>>>> so
>>>>>>>>>>>> you
>>>>>>>>>>>> just put text on the screen without a line ending. That could
>>>>>>>>>>>> be
>>>>>>>>>>>> one
>>>>>>>>>>>> contributing factor. Another might be you didn't put an
>>>>>>>>>>>> #include
>>>>>>>>>>>> <stdio.h>    statement in at the top of your program and maybe
>>>>>>>>>>>> used
>>>>>>>>>>>> #include<conio.h>. If that's the case, don't use printf with
>>>>>>>>>>>> conio.h
>>>>>>>>>>>> unless you also include stdio.h. For conio.h, cprintf is the
>>>>>>>>>>>> function
>>>>>>>>>>>> you want. Hope this helps.
>>>>>>>>>>>>
>>>>>>>>>>>> -----Original Message-----
>>>>>>>>>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>>>>>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of
>>>>>>>>>>>> ashish
>>>>>>>>>>>> rohtagi
>>>>>>>>>>>> Sent: Wednesday, April 13, 2011 8:04
>>>>>>>>>>>> To: programmingblind@xxxxxxxxxxxxx
>>>>>>>>>>>> Cc: punitdiwan@xxxxxxxxx
>>>>>>>>>>>> Subject: again a newbee question
>>>>>>>>>>>>
>>>>>>>>>>>> friends, sorry here I am with another foolish question, sorry
>>>>>>>>>>>> but
>>>>>>>>>>>> here
>>>>>>>>>>>> is no one to teach and I am learning myself. when I print any
>>>>>>>>>>>> text
>>>>>>>>>>>> on
>>>>>>>>>>>> screen using printf it quickly disappears. what should I do
>>>>>>>>>>>> that
>>>>>>>>>>>> it
>>>>>>>>>>>> should stay? take care, regards. ashish
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>>>>>>>> --
>>>>>>>>
>>>>>>>> Thanks,
>>>>>>>> Ty
>>>>>>>>
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>>>>>> Thanks,
>>>>>> Ty
>>>>>>
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>> Thanks,
>> Ty
>>
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