It goes right between the last printf statement and the return statement. It's job is to hold the program open at the end, so it should be the last statement before return, which ends the program.
On 4/13/2011 12:09 PM, ashish rohtagi wrote:
hi Tyler, thanks for your suggestion, but I am unable to understand where to put second scanf. will you just once show me? take care, regards. ashish On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx> wrote:Like ken said, use scanf to catch it before the window closes, or run it in a command line. Here's what's happening: You open the process, and the first scanf call blocks; that is to say, it will not process anything, it is simply waiting for the user to input something. But after it's done printing, there is no reason why it should stay open because you don't tell it to. So run from the command prompt, use getch() to let you hit enter before it closes or use another scanf. On 4/13/2011 9:32 AM, ashish rohtagi wrote:friends, thanks for all the encouragement. here is my problem, I want to use scanf fungtion. in input and output but as soon as I give my input and press enter the window disappears. it does not give output based on my input. here is the code. #include<stdio.h> int main() { char me[20]; printf("What is your name?"); scanf("%s",&me); printf("Glad to meet you, %s!\n",me); return(0); } On 4/13/11, Littlefield, Tyler<tyler@xxxxxxxxxxxxx> wrote:O. oops. In my defense, I haven't found coffee. :) On 4/13/2011 7:46 AM, Jared Wright wrote:It's there, just on the same line as the printf statement. On 4/13/2011 9:35 AM, Littlefield, Tyler wrote:good job on using int main, just don't forget a return 0; when you are done. between the printf and the closing brace. On 4/13/2011 6:36 AM, ashish rohtagi wrote:here is my code it compiles correctly but text just shows on the screen for 1 second, I want it to stay. #include<stdio.h> int main() { printf("I will learn programming!\n"); return(0); } On 4/13/11, DaShiell, Jude T. CIV NAVAIR 1490, 1, 26 <jude.dashiell@xxxxxxxx> wrote:You didn't put your printf statement in your message, but let me make a guess. You didn't put a (\n) in before the closing quote mark so you just put text on the screen without a line ending. That could be one contributing factor. Another might be you didn't put an #include <stdio.h> statement in at the top of your program and maybe used #include<conio.h>. If that's the case, don't use printf with conio.h unless you also include stdio.h. For conio.h, cprintf is the function you want. Hope this helps. -----Original Message----- From: programmingblind-bounce@xxxxxxxxxxxxx [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of ashish rohtagi Sent: Wednesday, April 13, 2011 8:04 To: programmingblind@xxxxxxxxxxxxx Cc: punitdiwan@xxxxxxxxx Subject: again a newbee question friends, sorry here I am with another foolish question, sorry but here is no one to teach and I am learning myself. when I print any text on screen using printf it quickly disappears. what should I do that it should stay? take care, regards. ashish __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind__________ View the list's information and change your settings at //www.freelists.org/list/programmingblind__________ View the list's information and change your settings at //www.freelists.org/list/programmingblind-- Thanks, Ty __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind__________ View the list's information and change your settings at //www.freelists.org/list/programmingblind-- Thanks, Ty __________ View the list's information and change your settings at //www.freelists.org/list/programmingblind__________ View the list's information and change your settings at //www.freelists.org/list/programmingblind
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