Dear Experts, I understood from some of the materials that the trace length between the driver to receiver ( signal path + return path) should be less than the rise time. Is my understanding correct? For example if the rise time of a signal is 1ns then the signal trace length should be less than 3 inches( signal trace length 3 inches and return path 3 inches totally 6 inches = 1 ns of signal travel delay which is equal to rise time of the signal) If my understanding is wrong can anybody please provide me with some materials to understand it. Sorry if this is bit basic question. Thank you very much. Mohamed Ali ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List technical documents are available at: http://www.si-list.net List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu