[SI-LIST] Re: Zodd Differential Calculation for Hspice w-element
- From: "Bill Beale" <beale@xxxxxxxxxxxxxx>
- To: <si-list@xxxxxxxxxxxxx>
- Date: Fri, 8 Aug 2003 09:45:05 -0700
Hi Vikas,
Lodd =3D L11 - L12
Codd =3D C11 - C12
Putting the numbers in:
Lodd =3D 4.00e-7 - 1.00e-7 =3D 3.00e-7
Codd =3D 1.00e-10 - (-3.00e-11) =3D 1.30e-10
Zodd =3D sqrt(Lodd/Codd)
=3D sqrt(3.00e-7/1.3e-10)
=3D 48.04
Yes, you need the maxwell matrices for both capacitance and inductance.
Thank you,
Bill
P.S. The first two equations assume a symmetric matrix.
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Bill Beale Phone: 503-439-3462
Sr. System App. Engineer Fax: 503-477-9472
Accelerant Networks e-mail: bill_beale@xxxxxxxxxxxxxx
On the world wide web @ http://www.accelerant.net
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>=20
>=20
> I have following Hspice w- element file for a pair of
> differential Stripline=20
>=20
> .MODEL diff_pair W MODELTYPE=3DRLGC, N=3D2
>=20
> + Lo =3D 4.00e-007
> + 1.00e-007 4.00e-007
>=20
> + Co =3D 1.00e-010
> + -3.00e-011 1.00e-010
>=20
> Ignoring Rs , Gd etc. can someone tell me what
> exactly is the Zodd ( differential ). I assume it will
> be=20
>=20
> Zodd(diff)=3D 2*sqrt((4.0e-7 -1.0e-7)/(1.0e-10
> +3.0e-11))
> =3D 96 Ohm
>=20
> What will be single Ended Impedence ?
>=20
> Z ( se ) =3D Sqrt (4.00e-007 / 1.00e-010 ) =3D 61 Ohm
>=20
> I am not sure if the Maxwellian "C" for single ended
> calculation should be taken as=20
>=20
> 1. C =3D 00e-010 or
> 2. C =3D 1.00e-010 - 3.00e-011=20
>=20
> Thanks
>=20
> Vikas
>=20
>=20
> =20
> =20
>=20
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