[SI-LIST] Re: Zodd Differential Calculation for Hspice w-element
- From: V S <for_si2003@xxxxxxxxx>
- To: si-list@xxxxxxxxxxxxx
- Date: Fri, 8 Aug 2003 10:30:42 -0700 (PDT)
Bill,
Is our assumption C11 = 1.00e-10 correct for the
Maxwellian matrix of hspice ?
Vikas
--- Bill Beale <beale@xxxxxxxxxxxxxx> wrote:
> Hi Vikas,
>
> Lodd =3D L11 - L12
> Codd =3D C11 - C12
>
> Putting the numbers in:
>
> Lodd =3D 4.00e-7 - 1.00e-7 =3D 3.00e-7
> Codd =3D 1.00e-10 - (-3.00e-11) =3D 1.30e-10
>
> Zodd =3D sqrt(Lodd/Codd)
> =3D sqrt(3.00e-7/1.3e-10)
> =3D 48.04
>
> Yes, you need the maxwell matrices for both
> capacitance and inductance.
>
> Thank you,
> Bill
>
> P.S. The first two equations assume a symmetric
> matrix.
>
>
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
> Bill Beale Phone: 503-439-3462
> Sr. System App. Engineer Fax: 503-477-9472
> Accelerant Networks e-mail:
> bill_beale@xxxxxxxxxxxxxx
> On the world wide web @ http://www.accelerant.net
>
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
> >=20
> >=20
> > I have following Hspice w- element file for a pair
> of
> > differential Stripline=20
> >=20
> > .MODEL diff_pair W MODELTYPE=3DRLGC, N=3D2
> >=20
> > + Lo =3D 4.00e-007
> > + 1.00e-007 4.00e-007
> >=20
> > + Co =3D 1.00e-010
> > + -3.00e-011 1.00e-010
> >=20
> > Ignoring Rs , Gd etc. can someone tell me what
> > exactly is the Zodd ( differential ). I assume it
> will
> > be=20
> >=20
> > Zodd(diff)=3D 2*sqrt((4.0e-7 -1.0e-7)/(1.0e-10
> > +3.0e-11))
> > =3D 96 Ohm
> >=20
> > What will be single Ended Impedence ?
> >=20
> > Z ( se ) =3D Sqrt (4.00e-007 / 1.00e-010 ) =3D 61
> Ohm
> >=20
> > I am not sure if the Maxwellian "C" for single
> ended
> > calculation should be taken as=20
> >=20
> > 1. C =3D 00e-010 or
> > 2. C =3D 1.00e-010 - 3.00e-011=20
> >=20
> > Thanks
> >=20
> > Vikas
> >=20
> >=20
> > =20
> > =20
> >=20
> > __________________________________
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