I have following Hspice w- element file for a pair of differential Stripline .MODEL diff_pair W MODELTYPE=RLGC, N=2 + Lo = 4.00e-007 + 1.00e-007 4.00e-007 + Co = 1.00e-010 + -3.00e-011 1.00e-010 Ignoring Rs , Gd etc. can someone tell me what exactly is the Zodd ( differential ). I assume it will be Zodd(diff)= 2*sqrt((4.0e-7 -1.0e-7)/(1.0e-10 +3.0e-11)) = 96 Ohm What will be single Ended Impedence ? Z ( se ) = Sqrt (4.00e-007 / 1.00e-010 ) = 61 Ohm I am not sure if the Maxwellian "C" for single ended calculation should be taken as 1. C = 00e-010 or 2. C = 1.00e-010 - 3.00e-011 Thanks Vikas __________________________________ Do you Yahoo!? Yahoo! SiteBuilder - Free, easy-to-use web site design software http://sitebuilder.yahoo.com ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List archives are viewable at: //www.freelists.org/archives/si-list or at our remote archives: http://groups.yahoo.com/group/si-list/messages Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu