[SI-LIST] Re: Inductance of parallel plate capacitors in series
- From: Andreas Hahn <andreas.hahn@xxxxxxxxxxx>
- To: "Traa, Boris" <boris.traa@xxxxxxxxxxx>
- Date: Wed, 12 Dec 2012 11:26:25 +0100 (CET)
Dear Boris,
If I may make a rather lower-brow analogy: consider the capacitor as a
McDonalds Big Mac (https://en.wikipedia.org/wiki/Big_Mac) with the meat
representing dielectric and the bread representing the plates.
The top and bottom plates are connected to the circuit, the middle plate
is not connected.
How does the inductance in this configuration change as compared with a
standard parallel-plate capacitor? (I am assuming the capacitance is
reduced to half and the breakdown voltage is doubled.)
On Wed, 12 Dec 2012, Traa, Boris wrote:
> Dear Andreas,
>
> Assume your two plates are fed in the center with a coaxial cable: upper
> plate with small hole for the inner wire connected to the shield and lower
> plate connected to the coaxial cable inner wire via the hole in the upper
> plate.
>
> What is in this set up supposed to represent the parasitic inductance of the
> capacitor?
>
> Kind regards
> Boris Traa
> System design engineer EMC
>
> It's the currents that make circuits work or fail.
>
> Philips Innovation Services/EMC center
> Room 2.020
> High Tech Campus 26
> 5656AE Eindhoven, The Netherlands
> Tel: ++ 31 40 27 43766
> Fax: ++ 31 40 27 42224
> E-mail: boris.traa@xxxxxxxxxxx
>
> -----Original Message-----
> From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On
> Behalf Of Andreas Hahn
> Sent: Wednesday 12 December 2012 9:58 AM
> To: si-list@xxxxxxxxxxxxx
> Subject: [SI-LIST] Inductance of parallel plate capacitors in series
>
> If we consider a simple parallel plate capacitor, the parasitic inductance of
> the plates decreases with the thickness of the dielectric.
>
> What happens to the parasitic inductance if we now build a second, identical
> capacitor on top of the first, such that one plate is now common to the two,
> and charge the two capacitors in series?
>
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