Hello Jason, I can understand your dilemma but you shouldn't treat source output impedance as a transmission line, due to its small size, it acts as a lumped element. When source launch a signal into transmission line (75 Ohm), It will see transmission line as a resistive load and thus launch voltage will be decided by voltage divider between source o/p impedance and transmission line characteristics impedance and as Steve pointed out loss will be only -4.44dB. If transmission line wouldn't have terminated with 75 Ohm in your case then reflected wave would have seen o/p impedance of source as a load and reflected coefficient for reflected wave would be 50-75/125 = 0.2 i.e. 20 % of reflected wave energy would have re-reflected. Hope that helps. Rgds, Rohit Mishra -----Original Message----- From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On Behalf Of Zhenwei Wang (zhenwwan) Sent: Thursday, June 07, 2012 2:36 PM To: si-list@xxxxxxxxxxxxx Subject: [SI-LIST] Re: Discussion: What is the extra attenuation if a 50ohm source interfacing a 75ohm cable which terminated with 75ohm? Error in description about calculation: the attenuation = 20lg(0.5)-20lg(0.4)=(-6db)-(-7.95db)=-1.95db. Sorry for inconvenience. BR Zhenwei(Jason) Wang Cisco Systems (Shanghai) Video Technology Co., Ltd. -----Original Message----- From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On Behalf Of Zhenwei Wang (zhenwwan) Sent: 2012年6月7日 16:42 To: si-list@xxxxxxxxxxxxx Subject: [SI-LIST] Discussion: What is the extra attenuation if a 50ohm source interfacing a 75ohm cable which terminated with 75ohm? Hi experts, Today I have a dicussion with my colleague. The topic is What is the extra attenuation if a 50ohm source interfacing a 75ohm cable which terminated with 75ohm resistor? Just like that when using a 75ohm cable connected to a 50ohm output instrument. The scenario is: Source(50ohm resistor)===>PointA===75ohm cable===>PointB || ||(75ohme resistor) GND My opinion: Based neglecting the multi-refection, there will be refection factor at pointA, which is 0.2. So 80% energy was launched into 75ohm cable. Then the voltage at pointB is Vin*0.8/2=Vin*0.4. But it should be 0.5*Vin at pointB. So the extra attenuation is 0.5-0.4=0.1==>-20db. Am I right? BR Zhenwei(Jason) Wang Cisco Systems (Shanghai) Video Technology Co., Ltd. ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List forum is accessible at: http://tech.groups.yahoo.com/group/si-list List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List forum is accessible at: http://tech.groups.yahoo.com/group/si-list List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu ------------------------------------------------------------------ To unsubscribe from si-list: si-list-request@xxxxxxxxxxxxx with 'unsubscribe' in the Subject field or to administer your membership from a web page, go to: //www.freelists.org/webpage/si-list For help: si-list-request@xxxxxxxxxxxxx with 'help' in the Subject field List forum is accessible at: http://tech.groups.yahoo.com/group/si-list List archives are viewable at: //www.freelists.org/archives/si-list Old (prior to June 6, 2001) list archives are viewable at: http://www.qsl.net/wb6tpu