Thank you Yuriy and Ryan for your responses. I already opened a ticket with
ANSYS for App Engineer assistance. However, from your #'s (Yuriy), it seems I
was getting the correct values from Q2D.
BTW, I had a typo in my original message; Q3D (not Q2D) was giving me
L=11.112nH/cm.
Thanks,
-Adnan
-----Original Message-----
From: Yuriy Shlepnev <shlepnev@xxxxxxxxxxxxx>
Sent: Thursday, September 3, 2020 11:59 AM
To: Yassin, Adnan <adnan.yassin@xxxxxxxxx>; si-list@xxxxxxxxxxxxx
Subject: RE: [SI-LIST] ANSYS Q2D & Q3D Extracted L & C
Hi Adnan,
As Ryan pointed out, support may answer your questions, Though, this is good
test and here are more numbers for your problem (assuming resistivity of metal
1.724e-8 Ohm*m):
Simbeor SFS @ 1 GHz (quasi-static - cross-section):
L= 2.3097 nH/cm; C= 2.458 pF/cm; Zo= 30.76Ohm; Simbeor 3DTF @ 1 GHz (3D EM -
extraction from line segment):
L= 2.3208 nH/cm; C= 2.493 pF/cm; Zo= 30.63Ohm;
Best regards,
Yuriy
-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On ;
Behalf Of Yassin, Adnan
Sent: Thursday, September 3, 2020 11:03 AM
To: si-list@xxxxxxxxxxxxx
Cc: Yassin, Adnan
Subject: [SI-LIST] ANSYS Q2D & Q3D Extracted L & C
Hi,
I have a trace 30um wide, with a thickness of 10um. It is a stripline with
dielectric thickness of 18um above and below the trace. The dielectric
coefficient is 4.5. Running these numbers through a tool on-line for impedance
calculations gives me slightly different numbers for L & C than ANSYS Q2D, but
totally different "L" number than ANSYS Q3D! Here is a summary of my data:
Online Calculator: L=1.888nH/cm, C=2.648pF/cm, and Zo&.704Ohm
ANSYS Q2D (@ 1GHz): : L=2.311nH/cm, C=2.508pF/cm, and Zo0.43Ohm
ANSYS Q3D (@ 1GHz): : L.112nH/cm, C=2.346pF/cm, and Zo=??
My questions:
1. Why "L" is much higher in Q3D compared to Q2D and the calculator? Is this
different inductance than what is reported by the latter two (e.g., loop
inductance vs. self inductance!)?
2. Can Zo in Q3D be calculated directly from these reported numbers by
applying the equation "SQRT(L/C)" or do I need to do some processing to "L"
first? Applying the equation to the #'s obtained above will give
SQRT(11.112nH/2.346pF)h.82Ohm, which is not realistic for my stackup (too high)!
Thanks,
-Adnan
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