Hi Adnan,
As Ryan pointed out, support may answer your questions,
Though, this is good test and here are more numbers for your problem
(assuming resistivity of metal 1.724e-8 Ohm*m):
Simbeor SFS @ 1 GHz (quasi-static - cross-section):
L= 2.3097 nH/cm; C= 2.458 pF/cm; Zo= 30.76Ohm;
Simbeor 3DTF @ 1 GHz (3D EM - extraction from line segment):
L= 2.3208 nH/cm; C= 2.493 pF/cm; Zo= 30.63Ohm;
Best regards,
Yuriy
-----Original Message-----
From: si-list-bounce@xxxxxxxxxxxxx [mailto:si-list-bounce@xxxxxxxxxxxxx] On
Behalf Of Yassin, Adnan
Sent: Thursday, September 3, 2020 11:03 AM
To: si-list@xxxxxxxxxxxxx
Cc: Yassin, Adnan
Subject: [SI-LIST] ANSYS Q2D & Q3D Extracted L & C
Hi,
I have a trace 30um wide, with a thickness of 10um. It is a stripline with
dielectric thickness of 18um above and below the trace. The dielectric
coefficient is 4.5. Running these numbers through a tool on-line for
impedance calculations gives me slightly different numbers for L & C than
ANSYS Q2D, but totally different "L" number than ANSYS Q3D! Here is a
summary of my data:
Online Calculator: L=1.888nH/cm, C=2.648pF/cm, and Zo&.704Ohm
ANSYS Q2D (@ 1GHz): : L=2.311nH/cm, C=2.508pF/cm, and Zo0.43Ohm
ANSYS Q2D (@ 1GHz): : L.112nH/cm, C=2.346pF/cm, and Zo=??
My questions:
1. Why "L" is much higher in Q3D compared to Q2D and the calculator? Is
this different inductance than what is reported by the latter two (e.g.,
loop inductance vs. self inductance!)?
2. Can Zo in Q3D be calculated directly from these reported numbers by
applying the equation "SQRT(L/C)" or do I need to do some processing to "L"
first? Applying the equation to the #'s obtained above will give
SQRT(11.112nH/2.346pF)h.82Ohm, which is not realistic for my stackup (too
high)!
Thanks,
-Adnan
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