[geocentrism] Re: Magnitude of scale CORRECTION
- From: "philip madsen" <pma15027@xxxxxxxxxxxxxx>
- To: <geocentrism@xxxxxxxxxxxxx>
- Date: Mon, 12 Nov 2007 06:53:52 +1000
You haven't addressed this question to any one so may I step into the breech?
With a list, everybody is the breech, to be stepped on , uh, in.
Philip.
----- Original Message -----
From: Jack Lewis
To: geocentrism@xxxxxxxxxxxxx
Sent: Monday, November 12, 2007 3:35 AM
Subject: [geocentrism] Re: Magnitude of scale CORRECTION
Dear Paul,
I addressed it to Neville. Your comment has been noted, many thanks.
Jack
----- Original Message -----
From: Paul Deema
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, November 11, 2007 5:08 PM
Subject: [geocentrism] Re: Magnitude of scale CORRECTION
Jack L
You haven't addressed this question to any one so may I step into the
breech?
If the Earth orbits the Sun CCW (looking down from the North) in 365.25
mean solar days (MSD) and also rotates CCW once in 365.25 MSD, then the Earth
will always present the same hemisphere to the Sun. Check it out with two
coins. If it revolves CCW in 365.25 MSD but does not rotate on its axis, then
it will have one 'day' per year but the Sun will rise in the West and set in
the East.
If the Earth in the same year of 365.25 MSD rotates CCW twice, then it will
have one 'day' (defined as sunrise - sunset - sunrise) per year yet it has
rotated 720 degrees. This and further examples will show that the Earth rotates
on its axis 365.25 + 1 = 366.25 times. This figure of 366.25 is in fact the
number of sidereal days.
Now the sidereal day is the time taken for 360 deg rotation and at this
time the stars will be in the same position they were one sidereal day earlier
but each MSD the Earth moves 360/365.25 = 0.98562... deg around its orbit and
this has the effect of rotating the daylight hemisphere 'backwards' by
0.98562... deg per day. So, ((360/365.25) / 360) * (24 * 60 * 60) = 236.55 s or
very close to 3 m 55.909 s which when added to 23 h 56 m 4.091 s is one MSD.
The short version is -- divide the length of one MSD by the number of MSDs
in a year and this will give you the difference between one MSD and one
sidereal day.
Paul D
PS I've just noticed that this was addressed to someone ie Neville J. I'm
definately getting old! However having spent the time, I'm not going to waste
the result. Apologies for upstaging.
----- Original Message ----
From: Jack Lewis <jack.lewis@xxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, 11 November, 2007 9:46:29 AM
Subject: [geocentrism] Re: Magnitude of scale CORRECTION
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