[geocentrism] Re: Magnitude of scale CORRECTION
- From: Paul Deema <paul_deema@xxxxxxxxxxx>
- To: geocentrism@xxxxxxxxxxxxx
- Date: Sun, 11 Nov 2007 17:08:30 +0000 (GMT)
Jack L
You haven't addressed this question to any one so may I step into the breech?
If the Earth orbits the Sun CCW (looking down from the North) in 365.25 mean
solar days (MSD) and also rotates CCW once in 365.25 MSD, then the Earth will
always present the same hemisphere to the Sun. Check it out with two coins. If
it revolves CCW in 365.25 MSD but does not rotate on its axis, then it will
have one 'day' per year but the Sun will rise in the West and set in the East.
If the Earth in the same year of 365.25 MSD rotates CCW twice, then it will
have one 'day' (defined as sunrise - sunset - sunrise) per year yet it has
rotated 720 degrees. This and further examples will show that the Earth rotates
on its axis 365.25 + 1 = 366.25 times. This figure of 366.25 is in fact the
number of sidereal days.
Now the sidereal day is the time taken for 360 deg rotation and at this time
the stars will be in the same position they were one sidereal day earlier but
each MSD the Earth moves 360/365.25 = 0.98562... deg around its orbit and this
has the effect of rotating the daylight hemisphere 'backwards' by 0.98562...
deg per day. So, ((360/365.25) / 360) * (24 * 60 * 60) = 236.55 s or very close
to 3 m 55.909 s which when added to 23 h 56 m 4.091 s is one MSD.
The short version is -- divide the length of one MSD by the number of MSDs in a
year and this will give you the difference between one MSD and one sidereal day.
Paul D
PS I've just noticed that this was addressed to someone ie Neville J. I'm
definately getting old! However having spent the time, I'm not going to waste
the result. Apologies for upstaging.
----- Original Message ----
From: Jack Lewis <jack.lewis@xxxxxxxxxxxx>
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, 11 November, 2007 9:46:29 AM
Subject: [geocentrism] Re: Magnitude of scale CORRECTION
CORRECTION - PLEASE RE-READ!
----- Original Message -----
From: Jack Lewis
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, November 11, 2007 9:32 AM
Subject: [geocentrism] Re: Magnitude of scale
Dear Neville,
I have a question regarding the rotation time.
The World takes 23h 56m 4.091s to rotate once about its axis. From where do we
get a measurement of time that is not related exactly to the time of the Sun's
orbit about the Earth? Why is there a 4 min. difference? This has always been a
puzzle to me.
Jack'
----- Original Message -----
From: philip madsen
To: geocentrism@xxxxxxxxxxxxx
Sent: Sunday, November 11, 2007 2:29 AM
Subject: [geocentrism] Re: Magnitude of scale
Are we all agreed so far?
Neville
Not entirely sure yet.. Neville said,
3. The World takes 23h 56m 4.091s to rotate once about its axis.
I am no math person, but instinct tells me that the 4 minutes is taken off
because of the increment of rotation needed to be caught up, due to the alleged
orbiting of the earth. It is not specifically the true spin rate.
It is 24 hours from sun rise to sun rise. Therefore in the HC scene, as the sun
is stationary, the real rotation is once in 24 hours.. the other figure is a
mathmatical compute to justify the differential in observation of the other
stars caused by the orbit al change in location.
Like I said.. Its only instinctive.. but I saw a diagram once somewhere. And
someone has to answer the connundrum I gave to Allen re the moon, and what IS
spin.
Philip.
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