I would do y*log(x) and the do the antilog after. -----Original Message----- From: foxboro-bounce@xxxxxxxxxxxxx [mailto:foxboro-bounce@xxxxxxxxxxxxx] On Behalf Of Bruley, Peter T Sent: Tuesday, April 27, 2010 2:31 PM To: 'Foxboro DCS Mail List' ('Foxboro DCS Mail List') Cc: Radtke, Richard W Subject: [foxboro] HLBL "to the power" expression Hi List Does anyone know how to do a power function x^y in HLBL? Similar to the pow(x,y) call under C or CALCA block EXP x y Thank you, Peter Bruley Xcel Energy | Responsible By Nature Plant Process Computer Analyst Sherburne County Generating Plant ________________________________________________ <blocked::blocked::http://www.xcelenergy.com/>XCELENERGY.COM<http://www. xcelenergy.com/> Please consider the environment before printing this email _______________________________________________________________________ This mailing list is neither sponsored nor endorsed by Invensys Process Systems (formerly The Foxboro Company). Use the info you obtain here at your own risks. Read http://www.thecassandraproject.org/disclaimer.html foxboro mailing list: //www.freelists.org/list/foxboro to subscribe: mailto:foxboro-request@xxxxxxxxxxxxx?subject=join to unsubscribe: mailto:foxboro-request@xxxxxxxxxxxxx?subject=leave _______________________________________________________________________ This mailing list is neither sponsored nor endorsed by Invensys Process Systems (formerly The Foxboro Company). Use the info you obtain here at your own risks. Read http://www.thecassandraproject.org/disclaimer.html foxboro mailing list: //www.freelists.org/list/foxboro to subscribe: mailto:foxboro-request@xxxxxxxxxxxxx?subject=join to unsubscribe: mailto:foxboro-request@xxxxxxxxxxxxx?subject=leave