Re: [foxboro] HLBL "to the power" expression

  • From: Jeremy Milum <jmilum@xxxxxxxxx>
  • To: foxboro@xxxxxxxxxxxxx
  • Date: Wed, 28 Apr 2010 11:48:10 -0500

On Wed, Apr 28, 2010 at 11:20 AM, Mike <mkessler@xxxxxxxxxxxx> wrote:
> You could use a Taylor's Series expansion in HLBL. Worked well for me.

yeah that could work, may take a lot of terms.

a^b = e^[b*ln(a)]

e^x = 1 + x/1! + x^2/2! + x^3/3! + ...

ln(x) = [(x-1)/x] + 1/2[(x-1)/x]^2 + 1/3[(x-1)/x]^3 + .....


-- 
Jeremy
 
 
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