[blind-chess] Re: Tournaments? was: Friendly game list
- From: Roderick Macdonald <rmacd@xxxxxxxx>
- To: blind-chess@xxxxxxxxxxxxx
- Date: Tue, 13 Apr 2010 08:44:26 -1000 (HST)
Hi Alvin,
I still have unread messages but here is a quick reply to your questions
regarding round-Robin versus Swiss tournaments:
In a Round-Robin, each player int he tournament plays each other player
once. If, for example, there are six players entered, then there are five
rounds. A "swiss" tournament is designed to accommodate any number of
players. After each round each player is paired against another player not
previously played against who has the same, or close to the same, score at
that time. If there are ten players entered, theory holds that you need
at least four rounds to determine a winner. this is because if a player
scores 4-0 after four rounds, no one else can have that same score because
the "winner" will have eliminated all other contenders.
Or put it this way: with 20 players entered, after one round there can
only be 10 players with a perfect 1-0. After two rounds there can only be
five with 2-0. After three rounds there can only be three with 3-0.
(Because of an odd number of players with 2-0, one will be paired with
someone with 1.5 if there are any, or one of the players with 1-1 if
necessary.) After four rounds there can be as many as two with 4-0 scores,
and after five rounds there can only be one with 5-0. so a minimum of five
rounds would be appropriate for 20 players.
Rod
oR PUT IT THIS WAY: iF 20 PLAYERS ARE ENTERED, THERE CAN ONLY BE 10 WITH
1-0 AFTER ONE ROUND. aFTER TWO ROUNDS THERE CAN ONLY BE FIVE WITH 2-0.
aFTER THREE ROUNDS THERE CAN ONLY BE THREE WITH 3-0. aFTER FOUR ROUNDS
THERE CAN ONLY BE TWO WITH 4-0. aND AFTER FIVE ROUNDS ONLY ONE PERSON CAN
HAVE 5-0, SO A MINIMUM OF FIVE ROUNDS WOULD BE NEEDED FOR 20 PLAYERS TO
DETERMINE A "PERFECT" WINNER.
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