In message <4eda0e13f4smart1@xxxxxxxxxxxxxxxxx> Chris <smart1@xxxxxxxxxxxxxxxxx> wrote thus: > I think GraphDraw does plot the axes/pips etc as one draw object, and > therefore the bounding box will be that of the whole graph area. I > haven't a clue what happens when you start to disconnect the > component bits. (Why would you need to?). Ahh - well, I wanted to reduce the overall size of the resultant diagram and decided to edit the axes to remove parts not needed. > > Anyway, I will have a look this weekend to see what GraphDraw > actually does when plotting the graph as a drawfile. It is some years > now since I did anything to it, and memory begins to fade. That's kind of you, many thanks. > If it is broken, as Martin very gently suggests, then I will try to > fix it. Not sure 'broken' is the correct word - I just mentioned it so that all the information was available. Actually, what I was reallly after was an app to draw a graph of a given equation. But calculating the co-ordinates and having GraphDraw plot them worked fine. -- Best Regards Eddie ------------------------------------------------------------ To change, suspend or cancel your subscription go to //www.freelists.org/list/artworks ------------------------------------------------------------