[SI-LIST] Re: Circle bus topology; Circular Firing Squad?
- From: ronald miller <ron@xxxxxxxxxxx>
- To: david.banas@xxxxxxxxxx
- Date: Fri, 03 Aug 2007 12:10:35 -0700
Hi Guys
Since all this theoretical garbage is still trailing on I would like to
suggest a simple analogy to make it clear.
Consider a 50 ohm microstrip on a board terminated in an open
Split the line lengthwise with a cut down the center -
each side will have approximately 100 ohm impedance if the other side is
removed.
TDR the two connected together at the source and you will again see 50 ohms.
Put a small solder ball at the end connecting the two lines
TDR the two again and you will again see 50 ohms.
The coupling factor can be igored for this analysis.
The idea that you have a circle is foolishness. It is one line split
into two forward paths and we know how they act.
Now, if you add different loads at different points along the two lines
you have a more complex situation
but can again analyze it without regard for the circle.
Ron Miller
David Banas wrote:
>I don't think it's correct to think of the electron and photon
>"collisions" as similar, since electrons are Fermions and photons are
>Bosons. Whereas Fermions are prohibited by the laws of quantum mechanics
>from occupying the same state and, therefore, must repel each other when
>they get close, Bosons are actually "encouraged" by quantum mechanics to
>occupy identical states. In fact, the more Bosons that are in a
>particular state, the more likely it is that a new one will join them.
>(This is why lasers work.)
>
>-db
>
>
>
>
>>-----Original Message-----
>>From: si-list-bounce@xxxxxxxxxxxxx
>>
>>
>[mailto:si-list-bounce@xxxxxxxxxxxxx]
>
>
>>On Behalf Of Muranyi, Arpad
>>Sent: Wednesday, August 01, 2007 11:13 AM
>>To: si-list@xxxxxxxxxxxxx
>>Subject: [SI-LIST] Re: Circle bus topology; Circular Firing Squad?
>>=20
>>This is why we need to use coloring dye... :-)
>>=20
>>Seriously, I wonder about the particle and
>>wave duality of electrons. Remember, the
>>drift velocity of electrons is not the same
>>as the propagation velocity of the EM waves.
>>=20
>>So what happens at the "collision" point (i.e.
>>the electrical midpoint of the loop)? Do=3D20
>>the electrons hit each other and bounce back
>>like balls with the drift velocity speeds,
>>while at the same time the waves go through
>>each other (at speeds close to c) without
>>changing directions?
>>=20
>>Another analogy comes to my mind, when two laser
>>beams on different path cross each other. After
>>the cross point we are still going to see their
>>original colors without any mixing. However,
>>if you did the same with two water streams,
>>the cross point will result in a splash in all
>>different directions...
>>=20
>>Is there someone out there with a good physics=3D20
>>background who could shed some light on this?
>>=20
>>Thanks,
>>=20
>>Arpad
>>
>>
>>
>=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D=
>3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D
>=3D3
>
>
>>D=3D
>>
>>
>>
>=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D=
>3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D=3D3D
>=3D3
>
>
>>D=3D
>>=3D3D
>>=3D20
>>=20
>>-----Original Message-----
>>From: si-list-bounce@xxxxxxxxxxxxx
>>
>>
>[mailto:si-list-bounce@xxxxxxxxxxxxx]
>
>
>>On Behalf Of Vinu Arumugham
>>Sent: Wednesday, August 01, 2007 10:45 AM
>>To: olaney@xxxxxxxx
>>Cc: weirsi@xxxxxxxxxx; erdinih@xxxxxxxxx; ron@xxxxxxxxxxx;
>>si-list@xxxxxxxxxxxxx
>>Subject: [SI-LIST] Re: Circle bus topology; Circular Firing Squad?
>>=20
>>Orin,
>>Since the reflected and propagated waves have identical properties
>>
>>
>and=3D20
>
>
>>are indistinguishable, how can you be sure it is one and not the
>>
>>
>other?
>
>
>>=20
>>Thanks,
>>Vinu
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>>=20
>>=20
>>
>>
>
>
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--
Ronald Miller
Ghz Data, Signal Integrity Consulting
7721 Sunset Ave.
Newark CA 94560
tel 510-793-4744
cell 510-377-9380
fax 510-742-6686
www.ghzdata.com
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