[pure-silver] Re: Mixing My Own Fixer
- From: "Richard Knoppow" <dickburk@xxxxxxxxxxxxx>
- To: <pure-silver@xxxxxxxxxxxxx>
- Date: Mon, 25 Oct 2010 11:03:03 -0700
----- Original Message -----
From: <JS2RT@xxxxxxx>
To: <pure-silver@xxxxxxxxxxxxx>
Sent: Monday, October 25, 2010 6:59 AM
Subject: [pure-silver] Re: Mixing My Own Fixer
I'm confused about how much ammonium thiosulfate to use
when converting a
formula that originally had sodium thiosulfate. For
example if the original
formula called for 240 grams of crystalline sodium
thiosulfate I multiply
the 240 grams by the ratio of the molecular weights to
get the new amounts.
If I am using anhydrous sodium thiosulfate I multiply by
158/248 and get
153 grams of anhydrous sodium thiosulfate. If I want to
use ammonium
thiosulfate in powder form I multiply by 148/248 and get
143 grams of powdered
ammonium thiosulfate.
As I understand it a 60% solution of liquid ammonium
thiosulfate has 60
grams of the chemical per 100 ml of the solution. So I
divide the 143 grams I
need by 60 grams/100 ml and come up with 238 ml of the 60%
solution as
being equivalent with the original 240 grams of
crystalline sodium thiosulfate.
Are my calculations correct?
That sounds correct. This is for a working solution.
Ammonium thiosulfate will dissolve in much greater quantity
than sodium thiosulfate so one can make up concentrated
stock solutions if desired. For a working solution its
interesting that the amount of 60% ammonium thiosulfate in
milliliters is essentially the same as the amount of sodium
thiosulfate, crystalline, in grams.
--
Richard Knoppow
Los Angeles, CA, USA
dickburk@xxxxxxxxxxxxx
=============================================================================================================
To unsubscribe from this list, go to www.freelists.org and logon to your
account (the same e-mail address and password you set-up when you subscribed,)
and unsubscribe from there.
Other related posts:
