I have some to experiment with but no time lately.
Nakka, Jolley, and Bindhammer all show XY results.
On Mon, Oct 1, 2018, 8:51 AM C J <dmarc-noreply@xxxxxxxxxxxxx> wrote:
Thank you for the efforts,
does anyone on this list use xylitol??
I have had good experiences. but i use it mainly because its cheap and
accessible for me.
Thank you,
Caine
On Monday, 1 October 2018, 6:58:08 pm AEST, Nikolai Nielsen <
nielsen.nikolai86@xxxxxxxxx> wrote:
i used the chemical equation to work out the ideal radio for xylitol but
when i made it it burned realllly badly so the 65/35 ratio seems to be the
best
Nikolai Nielsen
On Mon, 1 Oct 2018 at 10:56, C J <dmarc-noreply@xxxxxxxxxxxxx> wrote:
Can you please work out the ratio for kno3 and zylitol?/
Thank you
On Monday, 1 October 2018, 6:26:07 pm AEST, Nikolai Nielsen <
nielsen.nikolai86@xxxxxxxxx> wrote:
https://www.webqc.org/balance.php
Nikolai Nielsen
On Sun, 30 Sep 2018 at 21:38, Kenneth Irving <kenneth.irving@xxxxxxxxx>
wrote:
Chemistry does not restrict itself to stoichiometry.
El dom., 30 de sep. de 2018 a la(s) 16:18, Ray Rocket (
dmarc-noreply@xxxxxxxxxxxxx) escribió:
Oh, I think I just figured it out: just add extra glycerine to consume
the remaining oxygen. Kinda obvious in hindsight.
--------------------------------------------
On Sun, 9/30/18, Ray Rocket <dmarc-noreply@xxxxxxxxxxxxx> wrote:
Subject: [sugpro] Balancing Chemical Equations for Stoichiometric Sugar
Substitutions
To: sugpro@xxxxxxxxxxxxx
Date: Sunday, September 30, 2018, 1:11 PM
Hey All,
I've been doing some stoichiometric
calculations for sugar substitutions. Initially,
things were going well.
KNO3 balances with Dextrose and
Fructose at a ratio of 3.200:1 by weight and
KNO3 balances with Sucrose at a ratio
of 2.835:1.
However, when I tried to come up with a
balanced reaction for glycerine (C3H8O3) or propylene glycol
(C₃H₈O₂) with KNO3, a balanced chemical equation
wasn't forthcoming. Any suggestions? I'm sure
I'm missing something obvious, it's been a long time since I
did this kind of thing.
This is as close as I can get, but it
leaves a lot of unreacted oxygen on the right side of the
equation:
6(KNO3) + (C3H8O3) -> 3(N2) +
3(K2CO3) + 4(H2O) + 8.5(O2)
Any suggestions or recommendations?
Thanks in advance!
--
Kenneth
