[pure-silver] Re: Hydroquinone - would you like fries with that?
- From: Jean-David Beyer <jeandavid8@xxxxxxxxxxx>
- To: pure-silver@xxxxxxxxxxxxx
- Date: Tue, 03 May 2011 11:27:30 -0400
Richard Knoppow wrote:
> ----- Original Message -----
> From: "Gerald Koch" <gerald.koch@xxxxxxx>
> To: <pure-silver@xxxxxxxxxxxxx>
> Sent: Monday, May 02, 2011 9:45 PM
> Subject: [pure-silver] Re: Hydroquinone - would you like
> fries with that?
>
>
> It is the ortho and para positions that are usually
> photographically active.
> This is systematised by the Kendall - Pelz Rule. For
> example, hydroquinone and
> catechol are developing agents while resorcinol has little
> or no activity.
>
> I knew one was not active but thought it was the ortho,
> I guess its the meta.
>
> --
I had the same problem. I forgot which was ortho and which one was meta.
The OH group that turns benzene into phenol is in the root position.
Then follow ortho, meta, then para. So para aminophenol with have the
amino group opposite (in the 4 position) the OH; i.e., in the para
position. orthoaminophenol would have the amino group next to the OH.
Amidol (2,4 diaminophenol dihydrochloride) is a developer with the
amino groups in the para and ortho positions. It is so active it does
not require an activator such as borax, carbonate, etc., to develop.
--
.~. Jean-David Beyer Registered Linux User 85642.
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