Re: Here is my modified program, thoughts? corrections?

  • From: Jes <theeternalkid@xxxxxxxxx>
  • To: programmingblind@xxxxxxxxxxxxx
  • Date: Thu, 15 Jul 2010 15:34:45 -0400

Hi Ian,

Thanks for the help. I looked at your  suggestions  and it makes a little more 
sense I guess. I'll keep at it.


On Jul 15, 2010, at 3:24 PM, Ian D. Nichols wrote:

> Hi everyone,
>  
> There is a problem with Jes's logic here.  He wrote if (regNumber > 1 && 
> regNumber < 3).
>  
> But 1 is not greater than 1, and 3 is not less than 3, so the only number 
> that will be recognized here will be 2.
>  
> The if statement about 4 and 9 has the same problem.
>  
> What is meant, I feel sure, is
>  
> if (regNumber >= 1 && regNumber <= 3)
>  
> That will pick up 1, 2 or 3.  Similar operators in the 4 and 9 statement will 
> recognize all numbers from 4 to 9 inclusive.
>  
> I also think that there are difficulties with what is included in the while 
> loop and what isn't, but haven't looked closely at that yet.
>  
> HTH.
>  
> Ian
>  
> Ian D. Nichols,
> Toronto, Canada
>  
>  
> ----- Original Message -----
> From: Jes
> To: programmingblind@xxxxxxxxxxxxx
> Sent: Thursday, July 15, 2010 3:00 PM
> Subject: Re: Here is my modified program, thoughts? corrections?
> 
> Hi Jim,
> The statement which talks about 4 and 9 tells the program, if there are 
> between 4 and 9 registrants, the fee is 100 dollars.
> The whole thing goes like this:
> If a company enters  at least 1, up to 3 registrants, the fee is 150 dollars. 
> If they enter 4 to 9 registrants, the fee is 100 dollars, and if it is ten or 
> more people, it's 90 dollars.
> So, if I understand this correctly, Jim, if the first company entered 8 
> people and the second company entered 10, the total fee would be 
> 190 dollars. 100 dollars for the first 8 people, and then 90 dollars for the 
> other ten.
> Jes
> 
> On Jul 15, 2010, at 11:59 AM, Homme, James wrote:
> 
>> Hi,
>> I can't figure this out. Maybe you need to have && in the statement that 
>> talks about > 4 & < 9. But what's going on if it is either 4 or 9?
>> Jim
>> Jim Homme,
>> Usability Services,
>> Phone: 412-544-1810. Skype: jim.homme
>> Internal recipients,  Read my accessibility blog. Discuss accessibility 
>> here.Accessibility Wiki: Breaking news and accessibility advice
>> From: programmingblind-bounce@xxxxxxxxxxxxx 
>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Jes
>> Sent: Thursday, July 15, 2010 11:32 AM
>> To: programmingblind@xxxxxxxxxxxxx
>> Subject: Here is my modified program, thoughts? corrections?
>> ***program:
>> //Ch7AppE04.cpp
>>  //Displays total price of registrations.
>> //Created/revised by <Jes Smith on July 15, 2010.
>> #include <iostream>
>> #include <iomanip>
>> using std::cout;
>> using std::cin;
>> using std::endl;
>> //using std::fixed;
>> //using std::setprecision;
>> //declare variables
>> float totalPrice = 0;
>> float averagePayment = 0; 
>> int regNumber = 0;
>> //regNumber, The number of registrants stored in this variable.
>> //totalPrice The total cost for the company.
>> //averagePayment The payment the registrant makes to the company for 
>> attending the seminar.
>> int main()
>> {
>> cout << "Enter number of people who will be registered. \n Press enter after 
>> each number.\n Enter a negative number to get the total price: " << endl;
>> cin >> regNumber;
>>  while (regNumber >= 0)
>> {
>> cout << "Enter your next entry. Enter negative number to get total price: " 
>> <<endl;
>> cin >> regNumber;
>> } //endwhile
>> if (regNumber > 1 && regNumber < 3)
>> totalPrice = 150;
>> else if (regNumber > 4 < 9);
>> totalPrice = 100;
>>  if (regNumber >= 10)
>>  {
>>                 totalPrice = 90;}
>> totalPrice = (regNumber + totalPrice);
>> cout << regNumber << endl;
>> cout << totalPrice << endl;
>> return 0;
>> } //end of main function
>> 
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> 
>

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