RE: writing "recursive SQL"
- From: "Lex de Haan" <lex.de.haan@xxxxxxxxxxxxxx>
- To: <susanzlam@xxxxxxxxx>, <oracle-l@xxxxxxxxxxxxx>
- Date: Thu, 9 Sep 2004 21:37:15 +0200
check out the "connect by B = prior A start with A = <start value>" syntax.
this enables you to do a tree walk that will automatically stop when there
are no more child rows.
Kind regards,
Lex.
-------------------------------
visit http://www.naturaljoin.nl <http://www.naturaljoin.nl>
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skype me <callto://lexdehaan>
-----Original Message-----
From: oracle-l-bounce@xxxxxxxxxxxxx
[mailto:oracle-l-bounce@xxxxxxxxxxxxx]On Behalf Of susan lam
Sent: Thursday, September 09, 2004 20:27
To: oracle-l@xxxxxxxxxxxxx
Subject: writing "recursive SQL"
Hi,
I would like to write a SQL to recursively extract
data from a table.
The algorithm is as follows:
SQL> select * from mytable;
A B
---------- ----------
1 2
2 3
3 4
4 5
5 6
0 7
7 8
8 9
8 rows selected.
If A=3, output the corresponding value of B (ie 4),
then match B (ie 4) with A and output the next
corresponding value of B (ie 5) and so on...
Recursion stops when B != A
A & B are unqiue and A=<value> is a user input value
The result I'm looking for is:
if A=3, then the output is:
4
5
6
if A=7, then the output is:
8
9
Is there a way to accomplish that in SQL?
thanks.
susan
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