writing "recursive SQL"
- From: susan lam <susanzlam@xxxxxxxxx>
- To: oracle-l@xxxxxxxxxxxxx
- Date: Thu, 9 Sep 2004 12:27:16 -0700 (PDT)
Hi,
I would like to write a SQL to recursively extract
data from a table.
The algorithm is as follows:
SQL> select * from mytable;
A B
---------- ----------
1 2
2 3
3 4
4 5
5 6
0 7
7 8
8 9
8 rows selected.
If A=3, output the corresponding value of B (ie 4),
then match B (ie 4) with A and output the next
corresponding value of B (ie 5) and so on...
Recursion stops when B != A
A & B are unqiue and A=<value> is a user input value
The result I'm looking for is:
if A=3, then the output is:
4
5
6
if A=7, then the output is:
8
9
Is there a way to accomplish that in SQL?
thanks.
susan
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