Re: what does the op:11.4 mean?

  • From: "Jonathan Lewis" <jonathan@xxxxxxxxxxxxxxxxxx>
  • To: <oracle-l@xxxxxxxxxxxxx>
  • Date: Mon, 12 May 2008 17:55:37 +0100


LKR = LocK Row

Regards

Jonathan Lewis
http://jonathanlewis.wordpress.com

Author: Cost Based Oracle: Fundamentals
http://www.jlcomp.demon.co.uk/cbo_book/ind_book.html

The Co-operative Oracle Users' FAQ
http://www.jlcomp.demon.co.uk/faq/ind_faq.html


----- Original Message ----- From: "yuefu li" <liyuefu@xxxxxxxxxxxx>
To: <oracle-l@xxxxxxxxxxxxx>
Sent: Monday, May 12, 2008 2:26 PM
Subject: what does the op:11.4 mean?


hi all,

I create a dump file from logfile, for I want to know
why the redo file is so big. I found much op:5.1
followed by op:11.4.

I know op:5.1 is the information for undo, such as
insert(op:11.2), delete(op:11.3), update(op:11.5).
but I don't know what's for op:11.4.


such as:

REDO RECORD - Thread:1 RBA: 0x00b958.00000003.0100
LEN: 0x00d8 VLD: 0x01
SCN: 0x000d.22a825bf SUBSCN:  1 05/04/2008 14:59:56
CHANGE #1 TYP:0 CLS:18 AFN:74 DBA:0x1280fd97
SCN:0x000d.22a825bf SEQ:  1 OP:5.1
ktudb redo: siz: 72 spc: 5688 flg: 0x0022 seq: 0x0b3e
rec: 0x22
           xid:  0x0001.026.001bb38e
ktubu redo: slt: 38 rci: 33 opc: 11.1 objn: 7547 objd:
7547 tsn: 6
Undo type:  Regular undo       Undo type:  Last buffer
split:  No
Tablespace Undo:  No
            0x00000000
KDO undo record:
KTB Redo
op: 0x02  ver: 0x01
op: C  uba: 0x1280fd97.0b3e.21
KDO Op code: LKR row dependencies Disabled
 xtype: XA  bdba: 0x0cc0a309  hdba: 0x01c07d09
itli: 2  ispac: 0  maxfr: 4863
tabn: 0 slot: 53 to: 0
CHANGE #2 TYP:0 CLS: 1 AFN:51 DBA:0x0cc0a309
SCN:0x000d.22a825bf SEQ:  1 OP:11.4
KTB Redo
op: 0x02  ver: 0x01
op: C  uba: 0x1280fd97.0b3e.22
KDO Op code: LKR row dependencies Disabled
 xtype: XA  bdba: 0x0cc0a309  hdba: 0x01c07d09
itli: 2  ispac: 0  maxfr: 4863
tabn: 0 slot: 53 to: 2

ÀîÔ»¸£ Li Yuefu
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