Re: update year in date column
- From: "Philip Douglass" <philip.douglass@xxxxxxxxxxxxxxx>
- To: <oracle-l@xxxxxxxxxxxxx>
- Date: Tue, 23 Mar 2004 17:29:39 -0500
I'm not sure why you would be subtracting 1000 from the bad date, even if
you were actually subtracting years and not days. If I'm understanding you,
you really want to subtract 100 years from the bad dates. Try this: update
custtable set crdate = add_months(crdate, -(12*100));
Script started on Tue Mar 23 17:25:31 2004
$ sqlplus /
SQL*Plus: Release 8.1.7.0.0 - Production on Tue Mar 23 17:25:33 2004
(c) Copyright 2000 Oracle Corporation. All rights reserved.
Connected to:
Oracle8i Release 8.1.7.2.0 - Production
JServer Release 8.1.7.2.0 - Production
SQL> set lines 132 pages 50000
SQL> alter session set nls_date_format = 'MM/DD/YYYY HH24:MI:SS';
Session altered.
SQL> create table baddate (
2 cusno number(38,0) primary key,
3 cusname varchar2(15),
4 crdate date );
Table created.
SQL> insert into baddate values (
2 798489, 'GILBERT, ROSS',
3 to_date('09/16/2099 13:13', 'mm/dd/yyyy hh24:mi'));
1 row created.
SQL> insert into baddate values (
2 826744, 'HOEFLER, MATT',
3 to_date('10/08/2099 10:10', 'mm/dd/yyyy hh24:mi'));
1 row created.
SQL> insert into baddate values (
2 795126, 'FORT, JOETTA',
3 to_date('09/08/2099 15:15', 'mm/dd/yyyy hh24:mi'));
1 row created.
SQL> select * from baddate;
CUSNO CUSNAME CRDATE
---------- --------------- -------------------
798489 GILBERT, ROSS 09/16/2099 13:13:00
826744 HOEFLER, MATT 10/08/2099 10:10:00
795126 FORT, JOETTA 09/08/2099 15:15:00
SQL> update baddate set crdate = add_months(crdate, -(12*100));
3 rows updated.
SQL> select * from baddate;
CUSNO CUSNAME CRDATE
---------- --------------- -------------------
798489 GILBERT, ROSS 09/16/1999 13:13:00
826744 HOEFLER, MATT 10/08/1999 10:10:00
795126 FORT, JOETTA 09/08/1999 15:15:00
SQL> drop table baddate;
Table dropped.
SQL> exit
Disconnected from Oracle8i Release 8.1.7.2.0 - Production
JServer Release 8.1.7.2.0 - Production
$
script done on Tue Mar 23 17:27:09 2004
----- Original Message -----
From: "Barbara Baker" <barbarabbaker@xxxxxxxxx>
To: <oracle-l@xxxxxxxxxxxxx>
Sent: Tuesday, March 23, 2004 3:00 PM
Subject: update year in date column
OK, I'm just going to bite the bullet and claim total
ignorance here and see if someone takes pity on me :(
(sad face a nice touch, eh?)
Someone has accidently updated 378 records in the
customer table. The date changed from 1999 to 2099.
I need to change just the year back to 1999 for these
records. (I'd like to keep the time stamp, if
possible. The month and day are correct.) I looked
on metalink, google, and asktom. Some nice examples,
but not what I really need.
Thought I'd be clever and subtract 1000 from the date.
This works, but I don't know how to get it formatted
back into a date.
I'd prefer just sqlplus, but will use pl/sql if
necessary.
Here's what I've done so far:
(solaris 9 oracle 9.2.0.4)
JServer Release 9.2.0.4.0 - Production
DOC> CUSNO CUSNAME
CRDATE
DOC>---------- -----------------------------------
----------
DOC> 798489 GILBERT, ROSS
09/16/2099
DOC> 826744 HOEFLER, MATT
10/08/2099
DOC> 795126 FORT, JOETTA
09/08/2099
DOC>*/
SQL>
SQL> ---select to_date(to_char(crdate,'MM/DD/YYYY'))
from customer where cusno=798489;
SQL> ---update advdb.custtest_barb
SQL> ---set crdate= to_char(crdate,'MM/DD/YYYY'))
SQL> ---from customer where cusno=798489;
SQL>
SQL> select
to_date(to_char(crdate,'ddmmyyyy')-1000),'MM/DD/YYYY')
2 from customer where cusno=798489;
select
to_date(to_char(crdate,'ddmmyyyy')-1000),'MM/DD/YYYY')
*
ERROR at line 1:
ORA-00923: FROM keyword not found where expected
SQL>
SQL>
SQL> --- these both work
SQL> select to_char(crdate,'ddmmyyyy') from
custtest_barb where cusno=798489;
TO_CHAR(
--------
16092099
SQL> select to_char(crdate,'ddmmyyyy') - 1000 from
custtest_barb where cusno=798489;
TO_CHAR(CRDATE,'DDMMYYYY')-1000
-------------------------------
16091099
Thank for any assistance.
Barb
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