Hello, I have x=-46.627535509279 and y=-23.5411170208655 as coordinates. I need to convert its from 4326 to an equivalent ESRI SRID that is 102100. Oracle does not have 102100 it in the cs_srs view, so I need to choose one. I got a value using the sql statment below and with SRID 54004, but the X result is not equal. The Y value is near and I think that it I can use it. But the x result has difference. Look: select sdo_cs.transform( sdo_geometry(2001,4326, sdo_point_type(-46.627535509279, -23.5411170208655, null), null,null),54004) "Forth with rule" from dual; -- Query result X= -5190553,50983822 Y= -2680530,25761921 -- The expected value From wkid = 102100: X= -5190553.509838225 Y= -2697590.0847436045 The ESRI definition for SRID 102100 is : WGS_1984_Web_Mercator_Auxiliary_Sphere. I query in the cs_srs.wktext and there is no text like it. I also did the following pl/sql block in order to identify the SRID that should be a candidate: DECLARE CURSOR c1 IS SELECT x.srid, x.WKTEXT FROM cs_srs x WHERE wktext like 'PROJCS%' and srid NOT IN (2314); v_sql VARCHAR2(4000); v_geometry SDO_GEOMETRY; BEGIN DELETE FROM ERI_TRANSFORM; COMMIT; FOR l IN c1 LOOP v_geometry:= NULL; v_sql := 'select sdo_cs.transform(sdo_geometry (2001,4326, sdo_point_type(-46.627535509279, -23.5411170208655, null), null,null),' || l.srid || ') from dual'; DBMS_OUTPUT.PUT_LINE (V_SQL); BEGIN EXECUTE IMMEDIATE v_sql INTO v_geometry; insert into ERI_TRANSFORM (SRID, GEOMETRY) VALUES (L.SRID, V_GEOMETRY); COMMIT; EXCEPTION WHEN OTHERS THEN DBMS_OUTPUT.PUT_LINE ('ERRO PARA : ' || L.SRID); END; END LOOP; END; / I got three SRID`s: Mercator 49155 (based on NAD27 datum) --> I cannot use it. Miller Cylindrical 155648 (based on NAD27 datum) --> I cannot use it. World Mercator 54004 (based on WGS84 datum) --> The y values has different result Doubts: 1.) Is there any way to create an SRID in order to reproduce the expected value ? 2.) Is there any other way to convert SRID doing code instead using cs_transform oracle command ? Regards Eriovaldo