The break will probably take a while. The whole reason for the O(n^2) algorithm is so that you CAN break into it without corrupting anything. Cary Millsap Hotsos Enterprises, Ltd. http://www.hotsos.com * Nullius in verba * Upcoming events: - Performance Diagnosis 101: 8/10 Boston, 9/14 San Francisco, 10/5 = Charlotte - SQL Optimization 101: 7/26 Washington DC, 8/16 Minneapolis, 9/20 = Hartford - Hotsos Symposium 2005: March 6-10 Dallas - Visit www.hotsos.com for schedule details... -----Original Message----- From: oracle-l-bounce@xxxxxxxxxxxxx = [mailto:oracle-l-bounce@xxxxxxxxxxxxx] On Behalf Of Jared.Still@xxxxxxxxxxx Sent: Wednesday, August 04, 2004 1:12 PM To: oracle-l@xxxxxxxxxxxxx Subject: RE: Oracle 7.3.4 problem... SLOW Drop user > Jared / Everyone >=20 > Many Thanks for the input. > One quick question, the situation makes me nervous. Can I kill the = drop > session? Will the user still be there? >=20 Yes, it may take awhile for oracle to recognize the break, as it will be busy dropping a segment. The user will still be there, minus some tables and whatnot. I don't know what the internal procedures are in 7x for dropping a user, other than what Cary just told us about. I do know that it was not unusual for a drop user to cause an ORA-36, which is essentially 'recursion too deep'. Jared ---------------------------------------------------------------- Please see the official ORACLE-L FAQ: http://www.orafaq.com ---------------------------------------------------------------- To unsubscribe send email to: oracle-l-request@xxxxxxxxxxxxx put 'unsubscribe' in the subject line. -- Archives are at //www.freelists.org/archives/oracle-l/ FAQ is at //www.freelists.org/help/fom-serve/cache/1.html -----------------------------------------------------------------