RE: quick java question

I emailed you about this off list, but please pay very close attention to
what you are calling .hasNextFloat on.
 
Take care,
Sina

-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex Parks
Sent: Thursday, November 29, 2007 11:32 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: Re: quick java question

I think I found what is going on.  In your example you don't get input until
after you call hasNext...  but in my program I call it after I get input.
I, too, am quite tired and am heading to bed, but tomorrow when I can type
straight I will play with the arrangement of all those little statements
until I get something like your example instead of its opposite.  Thanks
again.

Have a great day,
Alex

> ----- Original Message -----
>From: "Jeffrey Fidler" <jfiddler2@xxxxxxxxxxx
>To: <programmingblind@xxxxxxxxxxxxx
>Date sent: Thu, 29 Nov 2007 23:12:51 -0500
>Subject: Re: quick java question

>This will test for a double.  Not exactly elegant -- I just did a
"find and
>replace" to get you the double.  Compiled and tested just in case
my tired
>mind has completely stopped working, but it is all ok.  :)  The
neat thing I
>noticed is that you'll get an integer number to work here, too as
it seems
>that the Scanner class will do the conversion from int to double
for you.
>In any case, I'm truly off to bed now!

>import java.util.Scanner;

>public class TestDbl {

> public static void main(String[] args) {
>  System.out.print("Please enter a double: ");
>  Scanner sc = new Scanner(System.in);
>  if (sc.hasNextDouble()) {
>  System.out.println("Your double is " + sc.nextDouble());
>  } else {
>  System.out.println("You did not enter an double!");
>  }
>  }
>}


>Kind regards,
>Jeff

>----- Original Message -----
>From: "Alex Parks" <mehgcap@xxxxxxx
>To: <programmingblind@xxxxxxxxxxxxx
>Sent: Thursday, November 29, 2007 11:07 PM
>Subject: Re: quick java question


>> Thanks.  My var is a double called bet (the assignment was a
blackjack
>> game, and no you are not helping me cheat by helping--we can use
whatever
>> to get it done).  I am ensuring bet is valid; that is, above 0,
below the
>> user's current balance, and a number and not a letter.  I have:
>> if (bet<pts || bet>0 || bet.hasNextDouble()


>> I get an error about bet not being able to be dereferenced.

>> Have a great day,
>> Alex

>>> ----- Original Message -----
>>>From: "Jeffrey Fidler" <jfiddler2@xxxxxxxxxxx
>>>To: <programmingblind@xxxxxxxxxxxxx
>>>Date sent: Thu, 29 Nov 2007 22:53:27 -0500
>>>Subject: Re: quick java question

>>>Here is an example using an integer.  (Sorry, but I had not
>> remembered that
>>>you were using a double when I began quickly working up this
>> example, and
>>>I'm off to bed for now.)  Remember that if you enter a char type,
>> it will
>>>still work as it will output the ascii value!  You can swap the
>> int for a
>>>double and it should work.  Hope this helps!

>>>import java.util.Scanner;


>>>public class TestInt {


>>>public static void main(String[] args) {

>>>System.out.print("Please enter an integer: ");

>>>Scanner sc = new Scanner(System.in);

>>>if (sc.hasNextInt()) {

>>>System.out.println("Your integer is " + sc.nextInt());

>>>} else {

>>>System.out.println("You did not enter an integer!");

>>>}

>>>}


>>>}



>>>Kind regards,

>>>Jeff



>>>----- Original Message -----
>>>From: "Sina Bahram" <sbahram@xxxxxxxxx
>>>To: <programmingblind@xxxxxxxxxxxxx
>>>Sent: Thursday, November 29, 2007 10:19 PM
>>>Subject: RE: quick java question


>>>> If you'd like some help on this tonight, shoot me the file off
>> list ...
>>>> I'm
>>>> busy tomorrow, but hopefully  Suzanne can help you then, if we
>> don't get
>>>> it
>>>> tonight?

>>>> sbahram@xxxxxxxxx

>>>> Take care,
>>>> Sina


>>>> -----Original Message-----
>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex
>> Parks
>>>> Sent: Thursday, November 29, 2007 9:55 PM
>>>> To: programmingblind@xxxxxxxxxxxxx
>>>> Subject: RE: quick java question

>>>> Okay, thanks! I will attach the .java file to an email and send
>> it to you
>>>> privately.  It will save my poor cs professor from answering all
>> my
>>>> questions and give me a new perspective.  Thanks again.

>>>> Have a great day,
>>>> Alex

>>>>> ----- Original Message -----
>>>>>From: "Suzanne Balik" <spbalik@xxxxxxxxxxxxxx
>>>>>To: programmingblind@xxxxxxxxxxxxx
>>>>>Date sent: Thu, 29 Nov 2007 21:30:35 -0500 (EST)
>>>>>Subject: RE: quick java question

>>>>>You typically use double's rather than float's in Java.  How
>>>> about this --
>>>>>would this work for you?

>>>>>Scanner sc = new Scanner(System.in); if (sc.hasNextDouble())
>>>>>  double value = sc.nextDouble();

>>>>>I'll be in my office some time after 3:00 PM tomorrow (Friday).
>>>> If you
>>>>>want to send me your code, I can help you with it then.

>>>>>Suzanne Balik





>>>>>> I tried it, but have changed the var to a float after I sent the 
>>>>>> message.  I tried var.hasNextFloat() but I get an error on that
>> line
>>>>>> that says something like "float cannot be dereferenced".  I am 
>>>>>> checking to be sure a number (the var in question) is greater
>> than 1
>>>>>> but less than another var and so thought I could just put this
>> simple
>>>>>> statement as another condition in the if statement, but I got
>> the
>>>>>> above error.  I am using the latest Java.

>>>>>> Have a great day,
>>>>>> Alex

>>>>>>> ----- Original Message -----
>>>>>>>From: "Suzanne Balik" <spbalik@xxxxxxxxxxxxxx
>>>>>>>To: programmingblind@xxxxxxxxxxxxx Date sent: Thu, 29 Nov 2007 
>>>>>>>21:00:11 -0500 (EST)
>>>>>>>Subject: RE: quick java question

>>>>>>>You can use the Scanner class to do what you want to do easily,
>>>>>> if you're
>>>>>>>using Java 5.0.  For example,

>>>>>>>Scanner sc = new Scanner(System.in); if (sc.hasNextInt())
>>>>>>>  int value = sc.nextInt();



>>>>>>>Suzanne Balik

>>>>>>>NC State University      EB II 2318    (919)515-5617

>>>>>>>We'll take a cup o' kindness yet, for auld lang syne.
>>>>>>>                                       --Robert Burns


>>>>>>>> Do a search for
>>>>>>>> Try catch tutorial
>>>>>>>> Try statements and catch clauses are the way to go if you are
>>>>>> going to
>>>>>>>> seriously work with java.


>>>>>>>> -----Original Message-----
>>>>>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of 
>>>>>>>> Alex
>>>>>> Parks
>>>>>>>> Sent: Thursday, November 29, 2007 7:55 AM
>>>>>>>> To: programmingblind@xxxxxxxxxxxxx
>>>>>>>> Subject: RE: quick java question


>>>>>>>> I am new to this language.  What do I put in place of "aString"
>>>>>>>> and how do I use the exception in my if statement? Add a 
>>>>>>>> throwsException to the end? Thanks.

>>>>>>>> Have a great day,
>>>>>>>> Alex

>>>>>>>>> ----- Original Message -----
>>>>>>>>>From: "Sina Bahram" <sbahram@xxxxxxxxx
>>>>>>>>>To: <programmingblind@xxxxxxxxxxxxx Date sent: Thu, 29 Nov 2007
>>>>>>>>>07:07:27 -0500
>>>>>>>>>Subject: RE: quick java question

>>>>>>>>>If you're expecting an integer, then you can do

>>>>>>>>>Integer.parseInt(aString)

>>>>>>>>>That will throw a NumberFormatException if it isn't a number.

>>>>>>>>>Take care,
>>>>>>>>>Sina


>>>>>>>>>-----Original Message-----
>>>>>>>>>From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>>>>>[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of 
>>>>>>>>>Alex
>>>>>>>> Parks
>>>>>>>>>Sent: Thursday, November 29, 2007 12:51 AM
>>>>>>>>>To: programmingblind@xxxxxxxxxxxxx
>>>>>>>>>Subject: quick java question

>>>>>>>>>Hi all,
>>>>>>>>>Is there a quick way of determining if the user input is a
>>>>>>>> number? I need it
>>>>>>>>>to be a number; it throws an exception and exits the program if
>>>>>>>> it isn't.
>>>>>>>>>Maybe something like:
>>>>>>>>>if (input!=\int
>>>>>>>>>I have no idea about the syntax, but something along those 
>>>>>>>>>lines
>>>>>>>> is what I
>>>>>>>>>am looking for.  Thanks for any help.

>>>>>>>>>Have a great day,
>>>>>>>>>Alex
>>>>>>>>>__________
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