RE: quick java question

If you'd like some help on this tonight, shoot me the file off list ... I'm
busy tomorrow, but hopefully  Suzanne can help you then, if we don't get it
tonight?

sbahram@xxxxxxxxx

Take care,
Sina


-----Original Message-----
From: programmingblind-bounce@xxxxxxxxxxxxx
[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex Parks
Sent: Thursday, November 29, 2007 9:55 PM
To: programmingblind@xxxxxxxxxxxxx
Subject: RE: quick java question

Okay, thanks! I will attach the .java file to an email and send it to you
privately.  It will save my poor cs professor from answering all my
questions and give me a new perspective.  Thanks again.

Have a great day,
Alex

> ----- Original Message -----
>From: "Suzanne Balik" <spbalik@xxxxxxxxxxxxxx
>To: programmingblind@xxxxxxxxxxxxx
>Date sent: Thu, 29 Nov 2007 21:30:35 -0500 (EST)
>Subject: RE: quick java question

>You typically use double's rather than float's in Java.  How
about this --
>would this work for you?

>Scanner sc = new Scanner(System.in);
>if (sc.hasNextDouble())
>  double value = sc.nextDouble();

>I'll be in my office some time after 3:00 PM tomorrow (Friday).  
If you
>want to send me your code, I can help you with it then.

>Suzanne Balik





>> I tried it, but have changed the var to a float after I sent the 
>> message.  I tried var.hasNextFloat() but I get an error on that line 
>> that says something like "float cannot be dereferenced".  I am 
>> checking to be sure a number (the var in question) is greater than 1 
>> but less than another var and so thought I could just put this simple 
>> statement as another condition in the if statement, but I got the 
>> above error.  I am using the latest Java.

>> Have a great day,
>> Alex

>>> ----- Original Message -----
>>>From: "Suzanne Balik" <spbalik@xxxxxxxxxxxxxx
>>>To: programmingblind@xxxxxxxxxxxxx
>>>Date sent: Thu, 29 Nov 2007 21:00:11 -0500 (EST)
>>>Subject: RE: quick java question

>>>You can use the Scanner class to do what you want to do easily,
>> if you're
>>>using Java 5.0.  For example,

>>>Scanner sc = new Scanner(System.in);
>>>if (sc.hasNextInt())
>>>  int value = sc.nextInt();



>>>Suzanne Balik

>>>NC State University      EB II 2318    (919)515-5617

>>>We'll take a cup o' kindness yet, for auld lang syne.
>>>                                       --Robert Burns


>>>> Do a search for
>>>> Try catch tutorial
>>>> Try statements and catch clauses are the way to go if you are
>> going to
>>>> seriously work with java.


>>>> -----Original Message-----
>>>> From: programmingblind-bounce@xxxxxxxxxxxxx
>>>> [mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex
>> Parks
>>>> Sent: Thursday, November 29, 2007 7:55 AM
>>>> To: programmingblind@xxxxxxxxxxxxx
>>>> Subject: RE: quick java question


>>>> I am new to this language.  What do I put in place of "aString"
>>>> and how do I use the exception in my if statement? Add a 
>>>> throwsException to the end? Thanks.

>>>> Have a great day,
>>>> Alex

>>>>> ----- Original Message -----
>>>>>From: "Sina Bahram" <sbahram@xxxxxxxxx
>>>>>To: <programmingblind@xxxxxxxxxxxxx Date sent: Thu, 29 Nov 2007 
>>>>>07:07:27 -0500
>>>>>Subject: RE: quick java question

>>>>>If you're expecting an integer, then you can do

>>>>>Integer.parseInt(aString)

>>>>>That will throw a NumberFormatException if it isn't a number.

>>>>>Take care,
>>>>>Sina


>>>>>-----Original Message-----
>>>>>From: programmingblind-bounce@xxxxxxxxxxxxx
>>>>>[mailto:programmingblind-bounce@xxxxxxxxxxxxx] On Behalf Of Alex
>>>> Parks
>>>>>Sent: Thursday, November 29, 2007 12:51 AM
>>>>>To: programmingblind@xxxxxxxxxxxxx
>>>>>Subject: quick java question

>>>>>Hi all,
>>>>>Is there a quick way of determining if the user input is a
>>>> number? I need it
>>>>>to be a number; it throws an exception and exits the program if
>>>> it isn't.
>>>>>Maybe something like:
>>>>>if (input!=\int
>>>>>I have no idea about the syntax, but something along those lines
>>>> is what I
>>>>>am looking for.  Thanks for any help.

>>>>>Have a great day,
>>>>>Alex
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